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2 years ago

Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8?

Mathematics

2 answers:

const2013 [10]2 years ago

5 0

The answer is c. Good luck!

Viefleur [7K]2 years ago

5 0

we have

$2x- 6 \geq 6(x- 2) + 8 \\ 2x-6\geq 6x-12+8\\ 2x-6x\geq -12+8+6\\ -4x\geq 2\\ -x\geq 0.5\\ x\leq -0.5$

the solution is the interval------> (-∞,-0.5]

see the attached figure

therefore

the answer is

the option C

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What is the missing length.

nasty-shy [4]

Answer:

$KS = 12$

Step-by-step explanation:

Given that ∆KLM ~ ∆RSK, $\frac{KL}{KR} = \frac{KM}{KS}$ (similarity theorem)

KL = 65

KR = 65 - 52 = 13

KM = 60

KS = ?

$\frac{65}{13} = \frac{60}{KS}$

Cross multiply

$65*KS = 60*13$

$65*KS = 780$

$\frac{65*KS}{65} = \frac{780}{65}$

$KS = 12$

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2 years ago

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3 years ago

What is the slope-intercept form of the equation y - 7= -5/2(x+4)

GREYUIT [131]

The first thing I would probably do is distribute (multiply) the -5/2 into the parenthesis:

= (-5/2)x + (-20/2)

Notice how I am not putting the x into the fraction. This is to make it easier to see the slope-intercept form.

Lets simplify the (-20/2) and then add 7 to both sides:

y - 7 = (-5/2)x - 10

y = (-5/2)x - 3

Your answer would then be:

y = (-5/2)x - 3

y = mx + b

Since it is now in the requested format.

4 0

2 years ago

What is another name for the set of all x-values from its graph

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For functions, it's solutions.

7 0

2 years ago

Read 2 more answers

Two perpendicular lines intersect on the -axis. The equation of one line is y- 4x-6=0. Determine the equation of the other line.

Kay [80]

Answer:

y = $-\frac{1}{4}$ x + 6 or y = $-\frac{1}{4}$ x - 0.375

Step-by-step explanation:

For 2 lines to be perpendicular, their slopes must be negative reciprocals. In order to find the perpendicular of y - 4x - 6 = 0:

SLOPE INTERCEPT FORM: y = 4x + 6

SLOPE OF LINE A: m=4

SLOPE OF LINE B (the one you are looking for): m= $-\frac{1}{4}$

Since I don't know if you meant that they intercept on the x or y axis I will do both.

y-axis

y-6= $-\frac{1}{4}$ (x-0)

y = $-\frac{1}{4}$ x+6

x-axis

y-0= $-\frac{1}{4}$ (x-1.5)

y= $-\frac{1}{4}$ x-0.375

7 0

2 years ago