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3 years ago

What effect can a buildup of pesticides have over the long term environment

1 answer:

5 0

A buildup of pesticides could get into an animal. That animal will be killed by a hunter. The hunter eats the animal with the pesticide. The hunter then becomes sick. This is just an example but you can see what i'm getting at.

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(PLZ READ, TRANSLATE IF U HAVE TOO)

Levart [38]

The translation is:
I just love the attention I get from all of you for a brief moment when writing these.

6 0

3 years ago

Read 2 more answers

What is the term for deep cold waters that replace warm surface waters?

Verdich [7]

Answer: This process is known as upwelling

Explanation:

6 0

3 years ago

A slice of pizza has 500 kcal. If the pizza is burned and its heat is used to warm a 50-L container of cold water, what would be

Vinvika [58]

Given:
The heat content of the pizza is Q = 500 kcal
The volume of the cold water is V = 50 L
The mass of a liter of cold water is 1 kg.

Calculate the mass, M, of cold water.
M = (50 L)*(1 kg/L) = 50 kg

The specific heat of water is
c = 4.184 kJ/(kg-K)

Also,
1 kcal = 4184 J, therefore
Q = (500 kcal)*(4184 J/kcal) = 2.092 x 10⁶ J

Let ΔT = increase in temperature of the cold water, °C (same as K).
Then
Q = M*c*ΔT
or
ΔT = Q/(M*c)
$\Delta T = \frac{(2.092 \times 10^{6} J)}{(50 \, kg)(4.184 \times 10^{3} \, \frac{J}{kg-K)}) } =10 \,K=10 \,^{o}C$

Answer: The temperature increases by 10 °C (or 10 K)

4 0

2 years ago

A _______cross explores two traits. dihybrid monohybrid multihybrid hybrid

Cloud [144]

Answer:

The correct option is A. dihybrid

Explanation:

A cross is drawn to generate the possible outcomes of traits being passed from parents to offsprings.

A monohybrid cross can be described as a cross in which only one trait is studied. For example, just studying the trait for eye colour.

A dihybrid cross can be described as a cross in which two traits are studies in a single cross. For example, studying the traits for eye colour and skin colour.

5 0

3 years ago

In humans, Rh-positive individuals have the Rh antigen on their red blood cells, while Rh-negative individuals do not. If the Rh

bixtya [17]

Answer: 60%

Explanation:

In population genetics, the Hardy-Weinberg Principle states that the genetic composition of a population remains in equilibrium as long as no natural selection or other factors are active and no mutations occur.

The frequencies of the genotypes of an individual locus will be set to a particular equilibrium value. It also specifies that these equilibrium frequencies can be represented as a simple function of the allelic frequencies at that locus. In the simplest case, with a locus with two alleles A and a, with allele frequencies of p and q respectively, the principle predicts that the genotypic frequency for the dominant homozygous AA is p^2, that of the heterozygous Aa is 2pq and that of the recessive homozygous aa, is q^2. The allele frequency of a is represented as p and the frequency of recessive allele is q.

The three genotypes AA : Aa : aa appear in a ratio p² : 2pq : q². If we add them up, we get the unit:

p^2 + 2pq + q^2 = (p + q)^2 = 1

And p + q = 1

Rh-positive genotypes are represented as AA (homozygous dominant) or Aa (heterozygous) since the presence of a single dominant allele is sufficient to express the phenotype. While Rh-negative genotypes are represented as aa.

If 84% of the population is Rh-positive, that means that this percentage includes all those who are AA and Aa. Then 16% are aa.

F(aa)=q^2=0.16

then F(a)=q=0.4

And since p + q = 1, p + 0.4 = 1, then p is 0.6

We can also calculate the rest, then F(AA)=p^2= 0.36

So F(Aa)= 2pq = 2 x 0.6 x 0.4 = 0.48

Notice that 0.36 + 0.16 + 0.48 = 1

3 0

2 years ago