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4 years ago

6

The area of a square garden is 128m sqared.how long is the diagonal

2 answers:

weqwewe [10]4 years ago

4 0

The area of a square is (side)².
If the area is 128m², then the side is (√128) meters. (That's 8√2.)

The diagonal is the hypotenuse of the right triangle you get
if you slice the square in half along the diagonal. Its length is
given in the words of Old Pythagoras:

   c² = a² + b²

'a' and 'b' are sides of the square, so

   c² = (√128)² + (√128)²

   =    2 (√128)²

c = √ (2 x 128) = √256 = 16 meters .

geniusboy [140]4 years ago

3 0

The length will be the square root of 128. Factoring out a 64, this is 8sqrt(2). To find the diagonal of square, multiply the length by sqrt(2), for a result of 8sqrt(2)*sqrt(2)=8*2=16.

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3y+10x-54=0 5y-2x-34=0<br><br> x=<br><br> y=

Blababa [14]

<h3>Answer:</h3><h2>x = 3 and y = 8 → (3, 8)</h2><h3>Step-by-step explanation:</h3>

$\left\{\begin{array}{ccc}3y+10x-54=0&\text{add 54 to both sides}\\5y-2x-34=0&\text{add 34 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}3y+10x=54\\5y-2x=34&\text{multiply both sides by 5}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3y+10x=54\\25y-10x=170\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\.\ \ \ \ \ 28y=224\qquad\text{divide both sides by 28}\\.\ \ \ \ \ \ \ \dfrac{28y}{28}=\dfrac{224}{28}\\.\ \ \ \ \ \ \ \boxed{y=8}$

$\text{put the value of y to the first equation}\\\\3(8)+10x=54\\24+10x=54\qquad\text{subtract 24 from both sides}\\24-24+10x=54-24\\10x=30\qquad\text{divide both sides by 10}\\\dfrac{10x}{10}=\dfrac{30}{10}\\\boxed{x=3}$

8 0

3 years ago

Determine the domain of the function

skelet666 [1.2K]

Answer:

Option B is correct.

The domain of the function h(x) is: $\{x | x\neq \pm 6 , x\neq 0\}$

Step-by-step explanation:

Domain states that the complete set of all the possible values of the independent variable where function is defined.

Given the function:

$h(x) = \frac{9x}{x(x^2-36)}$

To find the excluded value in the domain of the function.

equate the denominator to 0 and solve for x.

i.e

$x(x^2-36) = 0$

⇒x = 0 and $x^2-36 = 0$

⇒x = 0 and $x^2 = 36$

or

x = 0 and $x = \pm 6$

So, the domain of the function h(x) is the set of all real number except x = 0 and $x = \pm 6$

Therefore, the domain of the function h(x) is:

$\{x | x\neq \pm 6 , x\neq 0\}$

8 0

4 years ago

Read 2 more answers

PLSSSSS HELP ME BEST ANSWER GETS BRAINLIEST

cricket20 [7]

Answer:

40

Step-by-step explanation:

basexheight= area

8x10= 80

80/2=40

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4 0

3 years ago

Read 2 more answers

-2/5x3/5+5/2-3/5x1/6

d1i1m1o1n [39]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Suppose g(x) = f(x – 2) + 3. Which statement best compares the graph of g(x) with the graph of f(x)?

weqwewe [10]

Answer:

we conclude that g(x) = f(x – 2) + 3 means the graph of g(x) is shifted 2 units right and 3 units up.

Option A is correct

Step-by-step explanation:

To shift a function right

Subtract inside the function's argument. For example, $f(x - b)$ is basically $f(x)$ shifted b units to the right.

Subtracting inside the function's argument moves you to the right.

So, g(x) = f(x – 2) means f(x) is shifted two units to the right.

and to move a function up

Add outside the function. For example, $f(x) + b$ is basically $f(x)$ moved up $b$ units.

So, g(x) = f(x – 2) + 3 means, f(x) is moved 3 units up.

Therefore, overall, after two transformations, we conclude

that g(x) = f(x – 2) + 3 means the graph of g(x) is shifted 2 units right and 3 units up.

So, option A is correct.

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3 years ago