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3 years ago

What is the quotient of 6/9 divided 1/3

2 answers:

8 0

The answer is 2

Explanation:

6/8 can be simplifies to 2/3
Then use the KCF method (keep change flip)
2 3 2
— x — = — = 2
3 1 1

NeTakaya3 years ago

3 0

18/9, or 2/1. OR you can write that as 2

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Mia can run at a rate of 360 feet per minute. Approximately how many minutes would she take to run a 500-yard stretch of road an

tankabanditka [31]

Step-by-step explanation:

since we know, she can run 360 ft per minute, and we want to know how many minutes she would need to run 500 yards we need to find out how often 360 ft fit into 500 yards.

so,

500 yards / 360 ft

how can we make this division ?

help is given to us by taking us that 1 yard = 3 ft.

aha !

so, 500 yards = 500×3 ft = 1500 ft

therefore, our task now looks like

1500 ft / 360 ft

and this we understand and can do, right ?

1500 / 360 = 150/36 = 75/18 = 4 3/18 = 4 1/6 minutes

the closest answer option is therefore 4.2, meaning she would take about 4.2 minutes to run 500 yards.

7 0

2 years ago

Please help with the question in the picture!

Umnica [9.8K]

Answer: The answer would be 72/97

Step-by-step explanation: Sin = opposite/hypotenuse. So 72 is opposite angle C and 97 is the hypotenuse (Longest Side).

7 0

3 years ago

The base of an isosceles triangle is one and a half times the length of the other two sides. A smaller triangle has a perimeter

stira [4]

Answer:

P = 1.5x.

Step-by-step explanation:

Let the length of each side of the first triangle be x, then

Perimeter of this triangle

= 2x + 1.5x

= 3.5x.

So perimeter of smaller triangle is:

P = 1/2 * 3.5x

P = 1,.5x.

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2 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

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2 years ago

12<br>121 °<br>9<br>can it make a triangle if so what the area ?<br>

charle [14.2K]

Answer:

no it can not

Step-by-step explanation:

Triangle is always 180° in total.

7 0

3 years ago

Read 2 more answers