The answer would be 30 because the two given angles are proportionate to each other so if you find the side on the triangle with both lengths given you will see there is a scale factor of 5 so the corresponding segment on the other triangle is 6. Multiply by 5 then you will have 30 for x.
Answer:
the answer is going to be 496,000. If you meant "Thousandth" and not "Thousand" the answer is going to be 496,179.784
Ok, so 11:9
11-9 = 2
which means that 124= 2:1
124/2 = 62
so 62:0
now 11 x 62= 682
9 x 62= 558
so the ratio is 682:558
now 682 + 558 = 1,240
There are 1,240 total students in the school. 682 boys and 558 girls
Answer:
3.54 and 1.04
Step-by-step explanation:
Given:
Two towns are 1,100 miles apart.
A group of hikers Starts from each town and walks down the trail toward each other..
They meet after a total hiking time of 240 hours.
If one group travels 2 1/2 mile per hour slower than the other group.
<u>Question asked:</u>
Find the rate of each group.
<u>Solution:</u>
Let speed of faster hiker = 
Speed of slower hiker = 
<u>As we know:</u>
<u />
Total distance between two town = Total combined speed of both hikers
Total combined time taken


Speed of faster hiker =
= 3.54 miles per hour.
Speed of slower hiker =
=

Therefore, speed of faster hiker is 3.54 miles per hour and speed of slower hiker is 1.04 miles per hour.
Answer:
The net forces exerted on the horse and cart are not the same, so they are not balanced forces.
Step-by-step explanation:
Please see the Newton's 2nd Law which states that an object accelerates if there is a net or unbalanced force on it. In this scenario there is just one force exerted on the wagon i.e: the force that the horse exerts on it. The wagon accelerates because the horse pulls on it. And the amount of acceleration equals the net force on the wagon divided by its mass.
As there are two forces the push and pull the horse; the wagon pulls the horse backwards, and the ground pushes the horse forward. The net force is determined by the relative sizes of these two forces.
If the ground pushes harder on the horse than the wagon pulls, there is a net force in the forward direction, and the horse accelerates forward, and if the wagon pulls harder on the horse than the ground pushes, there is a net force in the backward direction, and the horse accelerates backward.
If the force that the wagon exerts on the horse is the same size as the force that the ground exerts, the net force on the horse is zero, and the horse does not accelerate.