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azamat
3 years ago
8

There are 38 Cube Houses. Each house could hold 1,000 unit cubes that are 1 meter by 1 meter by 1 meter. Describe the dimensions

of a cube house using unit cubes. Remember that the edges of a cube are all the same length. PLEASE HELP!
Mathematics
2 answers:
kvasek [131]3 years ago
5 0
So each house can hold 1000 cubes that are 1 meter in length. The house is also shaped like a cube, so you need to cube-root 1000. The cube-root of 1000 is 10. So the cube house has a length, width, and height of 10 meters.
Maksim231197 [3]3 years ago
5 0

The problem is giving us the total volume of each house (1000 unit cubes), and is asking us for the dimensions of the cube house.

We can solve this using the volume equation for the cube:

Volume_{cube} =Side_{cube} ^{3}

we solve for side (edge) which is what we look for

Side_{cube}=\sqrt[3]{Volume_{cube} }

Side_{cube}=\sqrt[3]{1000 unit cubes }\\Side_{cube}=10 unit cubes

like it is said in the problem the cube has the same dimensions for all three edges so the house would be 10 unit cubes high, 10 unit cubes deep and 10 unit cubes long

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2 years ago
Identify an equation in point-slope form for the line parallel to y = 1*-7 that
kakasveta [241]

<u><em>Answer:</em></u>

y + 2 = 1 (x+3) ............> y + 2 = x + 3

<u><em>Explanation:</em></u>

<u>The general form of the equation of a line in point-slope form is:</u>

y - y₁ = m (x - x₁)

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y = mx + c

<u>where:</u>

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<u>1- Getting the point:</u>

We are already given the point (-3 , -2) so we'll directly use it

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y = 1x - 7

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<u>This means that:</u>

slope of the line we want = 1

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Hope this helps :)

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I enter the bedroom. There are 34 people. You kill 30. How many people are in the bedroom?
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3 years ago
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Make 'h' as the subject. Remember to rationalize the denominator while solving.
Sliva [168]

Hello there BeGuiLE !

To solve your question,  we must first bring 'h' to one side of the equation.  Let's bring all the terms with the variable 'h' to the left side of the equation. So,
\large{\sf\sqrt{ 3  }  h =  1.6+h}
→ \large{\sf\sqrt{3}h-h=1.6 }

Now, let's combine the 2 terms containing the variable 'h'.
\large{\sf\sqrt{3}h-h=1.6 }
→ \large{\sf\left(\sqrt{3}-1\right)h=1.6 }

Now, we need to leave the variable 'h' alone in the left side of the equation & bring (√3 + 1) to the other side of the equation. This is done in order to make 'h' as the subject of the equation. So, we'll get it as,
\large{\sf\left(\sqrt{3}-1\right)h=1.6 }
→ \large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }

Now, let's rationalize it. Rationalizing is a process where we move the root from the denominator of a fraction to the numerator for easier calculation. So,
\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{(\sqrt{3}-1 )(\sqrt{3}+1}) }
Now, use the algebraic identity, (a + b)(a - b) = a² - b²
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{3-1} }
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{2} }
→ \boxed{\large{\sf\:h=0.8(\sqrt{3}+1)}}

Now, we've made 'h' as the subject of the equation. If you want to solve it more, then,
\large{\sf\:h=0.8(\sqrt{3}+1)}
Take √3 as 1.73 (approx. value up to 2 decimal places)
→ \large{\sf\:h=0.8(1.73+1)}
→ \large{\sf\:h=0.8(2.73)}
→ \boxed{\boxed{\huge{\bf{\:h=2.184 \: (approx.)}}}}

I hope this will help you.

Please refer to the attached image if the explanation shows some error.

_______

Check out more links which will help you understand the topic better :

■ brainly.com/question/21406377

■ brainly.com/question/696184

_______
\mathfrak{Lucazz}


4 0
3 years ago
Read 2 more answers
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