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Strike441 [17]
3 years ago
12

If x/5+6=-14 then x equals

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

x = - 100

Step-by-step explanation:

Given

\frac{x}{5} + 6 = - 14 ( subtract 6 from both sides )

\frac{x}{5} = - 20

Multiply both sides by 5 to clear the fraction

x = 5 × - 20 = - 100

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2 years ago
If AB = 10, AC = 6, and BC = 6, find AD:
JulsSmile [24]
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4 years ago
What is it called when the slope of a line is the same the entire length of the line ?
TEA [102]

Answer:

Slope

Step-by-step explanation:

The point of slope is that it is the same the entire length of the line.

4 0
4 years ago
What is the length of ST if RS=7?
nika2105 [10]
We can use tangent to calculate the length of ST.

\sf tangent=\dfrac{opposite}{adjacent}

Here, the opposite side of the 60 degree angle is ST, and the adjacent is RS. Plug in what we know, we can use 'x' for side ST:

\sf tan(60\textdegree )=\dfrac{x}{7}

Solve for 'x', multiply 7 to both sides of the equation:

\sf x=7tan(60\textdegree )

This is an exact answer for the length of ST, we can find an approximate with a calculator:

\sf x\approx 12.12
3 0
4 years ago
Read 2 more answers
Disregard my work, but how do you get the answer? There is also a graph at the bottom which is optional to use.
kakasveta [241]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)=  A(  Bx+  C)+  D
\\\\
~~~~y=  A(  Bx+  C)+  D
\\\\
f(x)=  A\sqrt{  Bx+  C}+  D
\\\\
f(x)=  A(\mathbb{R})^{  Bx+  C}+  D
\\\\
f(x)=  A sin\left( B x+  C  \right)+  D
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\
\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }  B\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{  C}{  B}\\
~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }  D\\
~~~~~~if\   D\textit{ is negative, downwards}\\\\
~~~~~~if\   D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind.

since the original or "parent" function is y = x²−4x+3, if we change the "x" argument to "x-2", we end up with a horizontal shift.

the x-2 part would be in the template the Bx+C part, with B = 1 and C = -2, or a horizontal shift to the right of 2/1 or 2 units.

since the parent function has a point at (2, -1), if we move that horizontally only to the right, we'd end up at (4, -1).
7 0
4 years ago
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