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bogdanovich [222]
3 years ago
13

Which translation will change figure ABCD to figure A′B′C′D′? (5 points)

Mathematics
1 answer:
mylen [45]3 years ago
6 0
6 units to the left and 7 units down will get you A'B'C'D
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Please help. Solve the triangle. Round ans to the nearest tenth.
White raven [17]

9514 1404 393

Answer:

  • C = 21°
  • a = 13.3
  • c = 5.4

Step-by-step explanation:

The third angle can be found from the sum of angles in a triangle.

  A + B + C = 180°

  C = 180° -62° -97°

  C = 21°

__

The remaining side lengths can be found using the Law of Sines.

  a/sin(A) = b/sin(B)

  a = sin(62°)(15/sin(97°)) ≈ 13.34

Similarly, ...

  c/sin(C) = b/sin(B)

  c = sin(21°)(15/sin(97°)) ≈ 5.42

The remaining side lengths are approximately ...

  a ≈ 13.3

  c ≈ 5.4

4 0
3 years ago
-15<br> π<br> + 12<br> π<br> - 5<br> π<br> =
Ksju [112]

Answer:

-8π or -25.13

Step-by-step explanation:

8 0
3 years ago
What are the two missing sides of the triangle ??
igor_vitrenko [27]
Remark
It's a right triangle so the Pythagorean Theorem applies. All you have to do is put the right things in the right places of the formula.

Givens
a = x
b = x + 4
c = 20

Formula and Substitution.
a^2 + b^2 = c^2
x^2 + (x + 4)^2 = 20^2

Solution
x^2 + x^2 + 8x + 16 = 20 Collect the like terms on the left.
2x^2 + 8x + 16 = 20  Subtract 20 from both sides.
2x^2 + 8x + 16 - 20 = 0  
2x^2 + 8x - 4 = 0         Divide through by 2
x^2 + 4x - 2 = 0

Use the quadratic formula
a = 1
b = 4
c = - 2

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a} &#10; 
\text{x = }\dfrac{ -4 \pm \sqrt{4^{2} + 4(1)(2) } }{2} &#10;

From which x = (-4 +/- sqrt(24) ) / 2
x1 = (- 4 +/- sqrt(4*6) ) / 2
x1 = (- 4 +/- 2 sqrt(6) ) / 2
x1 = -2 + sqrt(6)
x2 = -2 - sqrt(6)  This is an extraneous root. No line can be minus.

x1 = + 0.4495
x2 = x + 4 = 4.4495
6 0
3 years ago
Circumference and area of a circular piece of glass
Vadim26 [7]

Answer:

Area = πr²

Circumference = 2πr

You can use pie as both 22/7 Or 3.14

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

8 0
2 years ago
Help 8th grade math pls ;-;
Sever21 [200]

Answer:

19.1 feet

Step-by-step explanation:

Length of the ladder = 20 feet

Distance from the ladder to the wall = 6 feet

Height of the ladder on the wall = x

x² + 6² = 20²

x² = 20² - 6²

x² = 364

x = 19.1 feet (Rounded to nearest tenth)

6 0
2 years ago
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