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Dovator [93]
3 years ago
14

You make $ 304 a day on a job. What will you receive for working frac(1,16) of the day?

Mathematics
1 answer:
Nitella [24]3 years ago
5 0
304 (pay per day) * 1/6 (amount of the day you worked).
304 * 1/6 (0.1666666666) = 50 and 2/3 or 50.666666666
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What is 1/3x1/3x1/3 in exponents
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3 0
3 years ago
Show how you can use the distributive property to rewrite and find (32x6)+(32x4)
Nikitich [7]
32(6+4) =320 you need to find the common term and then place on ouside of the parentheses
8 0
3 years ago
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If h is a linear function with h(1) = 10 and h(3) = -6, what is h(5)?
Ghella [55]

Answer:

h(5) = - 22

Step-by-step explanation:

Given that h is a linear function say, h(x) = ax + b ......... (1)

Now, given that h(1) = 10 and h(3) = - 6  

Hence, we can write from equation (1), a(1) + b = 10, ⇒ a + b = 10 .......... (2)

And a(3) + b = - 6, ⇒ 3a + b = - 6 ........ (3)

Now, solving equations (2) and (3) we get (3a - a) = - 6 - 10

⇒ 2a = - 16

⇒ a = - 8

So, from equation (2), we get, b = 10 - a = 18  

Therefore, the linear function is

h(x) = - 8x + 18

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5 0
4 years ago
The total cost in dollars for Larry to have his birthday party at a local
luda_lava [24]

Answer:

0 \leq p < 6

Step-by-step explanation:

Given

t = 6.95p + 29.95

Amount = 70

Required

Determine the domain

First, we need to solve for p

Substitute 70 for t in t = 6.95p + 29.95

70 = 6.95p + 29.95

Collect Like Terms

6.95p = 70 - 29.95

6.95p = 40.05

Solve for p

p = 40.05/6.95

p = 5.76

This implies that Larry can not invite up to 6 people.

Hence, the domain can be represented as: 0 \leq p < 6

7 0
3 years ago
what is the equation in point slope form of the line that is parallel to the given line and passes through the point (-3,1)?
Aleks04 [339]

Because you didn't give the line, it is impossible to write it completely. However, the line would be y - 1 = m(x + 3), in which m is the slope in the line.

We know this firstly because parallel lines have the same slope. So whatever the slope is to the given line, it must match the point-slope form.

So, we'll call this mystery slope m and then use the point in plug in the point into point-slope form.

y - y1 = m(x - x1)

y - 1 = m(x - -3)

y - 1 = m(x + 3)

5 0
3 years ago
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