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4 years ago

Given: AB = 12 AC = 6 Prove: C is the midpoint of AB.

Mathematics

1 answer:

Andrew [12]4 years ago

6 0

Answer:

Line AC is the half of libe AB

Step-by-step explanation:

Let's define a midpoint.

Mid point it the point or line that divides a line in to two equally parts.

So if line AB = 12

The midpoint with any dimensions should be a line that divides it into two.

12/2 = 6

So the midpoint is a line that lies at the point of 6

So dimensions l of AC = 6

AC is the midpoint of AB

So it means that C i.e point C is the midpoint of line AB

making line AC the half of line AB

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3 years ago

Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.

dmitriy555 [2]

see the attached figure to better understand the problem

we have that

$cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units$

Step 1

Find the value of AC

we know that

in the right triangle ABC

$cos (A)=(AC/AB)\\AC=AB*cos(A)$

substitute the values in the formula

$AC=12*(1/5)\\ AC=2.4\ units$

Step 2

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we know that

in the right triangle ABC

Applying the Pythagorean Theorem

$AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}$

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Step 3

Find the value of BD

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$BD^{2} =DC^{2}+BC^{2}$

substitute the values

$BD^{2} =2^{2}+11.76^{2}$

$BD=11.93\ units$

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the length of BD is 11.93 units

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