How do you solve...0=-5t^2+20t+1

1 answer:

4 0

There were 2 solutions that i came up with. Here is the first one. I rearranged the eqaution by subtracting what is to the right of thr equal sign. Multiply the coefficeint of the first term by the constant 5 x (-1)= -5. Then you would find 2 factors of -5 whose sum equals the coefficient of the middle term which is 20. -5+1= -4 and -1+5=4. the eqaution then comes to 5t^2-20t-1=0. you would solve 5t^2-20t-1=0. you would divide both sides of the equal sign by 5. t^-4t-1/5=0. then t^2-4t=1/5. add 4 to both sides of the equation. so we get 21/5+ 4 + 4t -t^2=21/5. it then comes out to be t^2-4t+t=t-2^2. according to the law of transitivity it is t-2^2=21/5.

t =(20+√420)/10=2+1/5√<span> 105 </span><span>= 4.049 </span>.

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Mark's dad is three times older than Mark. Mark's sister is 2 years younger than Mark. (3m) The sum of their ages is 48. How old

nataly862011 [7]

Answer:

Age of Mark $=10$ years

Age of Mark's dad $=30$ years

Age of Mark's sister $=8$ years

Step-by-step explanation:

Let age of Mark be $x$ years.

Mark's dad is three times older than Mark

Age of her Mark's dad $=3x$

Mark's sister is 2 years younger than Mark

Age of Mark's sister $=(x-2)$ years

The sum of their ages is 48.

$x+3x+x-2=48\\5x-2=48\\5x=50\\x=10$

Age of Mark $=x=10$ years

Age of Mark's dad $=3x=3(10)=30$ years

Age of Mark's sister $=x-2=10-2=8$ years

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3 years ago

Square ABCD is dilated by a scale factor of 2 with the center of dilation at the origin to form square ABCD . What are the coord

kobusy [5.1K]

Answer:

B'(16,14)

Step-by-step explanation:

In square ABCD, A(2,7) C(8,1) D(2,1). First, find the coordinates of the vertex B. From the attached diagram you can see that CD=6 units and is parallel to the x-axis, AD=6 units and is parallel to the y-axis. So, B(8,7).

The origin O is the center of dilation, 2 is the scale factor. The rule of the dilation is

(x,y)→(2x,2y)

Thus,

B(8,7)→B'(16,14) (see attached figure).