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Keith_Richards [23]
4 years ago
15

Use elimination (adding or subtracting) to find the common solution

Mathematics
1 answer:
Leokris [45]4 years ago
7 0

A) The solution (x,y) is (9,-2).

B) The solution (x,y) is (6, -1/2).

C) The solution (x,y) is (-5,2).

D) The solution (x,y) is (1, -10).

<u>Step-by-step explanation:</u>

A) x+y=7 and x+2y=5

Subtract the second equation from the first equation.

 x+y = 7

-(<u>x+2y = 5</u>)

 <u>   -y  = 2</u>

⇒ y = -2

The value of y is -2.

Substitute y= -2 in any of the equation.

⇒ x + (-2) = 7

⇒ x = 7+2

⇒ x = 9

The value of x is 9.

The solution (x,y) is (9,-2).

B) x+2y=5 and x-2y=7

Add both the equations.

x + 2y = 5

<u>x - 2y = 7 </u>

<u> 2x     = 12</u>

⇒ x = 12/2

⇒ x = 6

The value of x is 6.

Substitute x= 6 in any of the equations.

⇒ 6 + 2y = 5

⇒ 2y = 5-6

⇒ 2y = -1

⇒ y = -1/2

The value of y is -1/2.

The solution (x,y) is (6, -1/2).

C) x+4y=3 and -x+y=7

Add both the equations.

x + 4y = 3

<u>-x + y = 7 </u>

<u>    5y = 10</u>

⇒ y = 10/5

⇒ y = 2

The value of y is 2.

Substitute y=2 in any of the equations.

⇒ -x + 2 = 7

⇒ -x = 7-2

⇒ -x = 5

⇒ x = -5

The value of x is -5.

The solution (x,y) is (-5,2).

D) 5x-2y=25 and 4x-2y=24

Subtract the second equation from the first equation.

  5x - 2y = 25

- (<u>4x - 2y = 24</u>)

   <u>  x        = 1  </u>

The value of x is 1.

Substitute x=1 in any of the equations.

⇒ 5(1) - 2y = 25

⇒ 5 -2y = 25

⇒ -2y = 25-5

⇒ -2y = 20

⇒ y = -20/2

⇒ y = -10.

The value of y is -10.

The solution (x,y) is (1, -10).

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