Write an inequality equation equivalent to 3x – 4y = 8?

Mathematics

1 answer:

Natalka [10]3 years ago

4 0

Answer:

3x-4y=8

-4y=8-3x (subtracting 3x from each side of the equation)

-4y/-4=(8-3x)/-4 (dividing each side of the equation by -4)

y=-2+3/4x

y=3/4x-2

Step-by-step explanation:

Hope you like my answer

lol

You might be interested in

Charles and Lisa were having a watermelon eating contest. They ate twelve slices of watermelon between the two of them. Lisa ate

skad [1K]

The answer should be C. 8 because two times the amount that Charles ate which is 4 equals 8 and 4+8=12

6 0

2 years ago

Read 2 more answers

Calculate the area of a circle with a diameter of 8 feet

sattari [20]

Answer: 50.27

Step-by-step explanation:

Area = pi r^2

= pi x 16

4 0

2 years ago

Read 2 more answers

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$