Explain the difference between 2x^3 and (2x)^3?

1 answer:

5 0

With our the parenthesis, you would only be multiplying the x to the third powerb but with them you would multiply the 2x first and then what ever answer you get would e to the third power. Hope this helps, I'm not the best at explaining things.

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Write an equivalent expression in standard form.<br><br> (2x + 5)(x + 1)

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2x^2+7x+5

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The points (2, r) and (6, -4) lie on a line with slope 4. Find the missing coordinate r<br> R=

Rus_ich [418]

$\text{The slope-intercept form:}\ y=mx+b\\\\\text{We have:}\ m=4\\\\\text{then}\ y=4x+b\\\\\text{The line passes through point (6; -4). Substitute:}\\\\(6;-4)\to x=6;\ y=-4\\\\-4=4\cdot6+b\\-4=24+b\ \ \ |-24\\b=-28\\\\\text{therefore:}\ y=4x-28$
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dexar [7]

(9x^2 + 21x + 10)= (3x+5)( 3x+2)+0

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A restaurant owner was experimenting with the taste of her homestyle lemon drink. She started with 60 litres of water. She remov

Burka [1]

Answer:

ratio of pure lemon juice to water in the homestyle lemon drink is 5 : 19.

Step-by-step explanation:

In order to solve the final ratio of lemon juice to water, let us start by determining the initial ratio of pure lemon juice to water in the first mix. This is done as follows:

Total volume of mixture = 60 liters

initial volume of water = 60 liters

initial volume of lemon juice = 0 liters

1) She removed 15 liters of the water and replaced it with 15 liters of pure lemon juice.

Volume of water = 60 - 15 = 45 liters

Volume of lemon juice = 15 liters

$\therefore \frac{15}{60}\ = \frac{1}{4}\ of\ the\ first\ mix\ is\ lemon\ juice\\\frac{45}{60}\ = \frac{3}{4}\ of\ the\ first\ mix\ is\ pure\ water$

2) She removed 10 liters of the new mixture

Let us convert this amount removed into ratio:

$lemon\ juice\ = \frac{1}{4}\ \times 10 = \frac{10}{4} = \frac{5}{2}\ liters.\\ \therefore the\ owner\ removes\ \frac{5}{2}\ liters\ of\ pure\ lemon\ juice\\pure\ water\ = \frac{3}{4}\ \times 10 = \frac{30}{4} = \frac{15}{2}\ liters\\ \therefore\ the\ owner\ removes\ \frac{15}{2}\ liters\ of\ water\ from\ the\ first\ mix.$

New volumes of water and lemon juice after removing the 10 liters of mixture is calculated as follows:

$lemon\ juice\ = 15 - \frac{5}{2} = \frac{30-5}{2} = \frac{25}{2}\ liters\ of\ lemon\ juice\\pure\ water\ = 45 - \frac{15}{2} = \frac{90-15}{2} = \frac{75}{2}\ liters\ of\ pure\ water$