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3 years ago

Choose the best answer that represents the property used to rewrite the expression.

Mathematics

1 answer:

cricket20 [7]3 years ago

6 0

Product property is the answer

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HELP! HELP! SAVE ME FROM THIS NIGHTMARE!!!

bazaltina [42]

Answer: x ≥ 6

Step-by-step explanation:

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3 years ago

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Mark has a shipping business. If your package weighs 2 pounds or less, the shipping costs $4. If your package weighs more than 2

maks197457 [2]

So far I have:

(1.25 + 1) if x is in the interval (-inf,7]
(2.25 +1) if x is in the interval (7,13)
(3.50+1+3) if x is in the interval [13,inf)

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3 years ago

Which option best describes the polynomial?

liq [111]

Degree of ploynominal is the largest exponent you find, which is here the 4x to the 6th. there are only two terms here.

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3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

Find the distance between the points R(0,5) and S(12,3). round the answer to the nearest tenth

Burka [1]

12.2

((12) - (0))^2 + ((3) - (5))^2

5 0

3 years ago