All categories

3 years ago

What is the range of the function on the graph

Mathematics

2 answers:

ololo11 [35]3 years ago

5 0

Y is less than it equal to 3

meriva3 years ago

4 0

Answer:

Y ≤ 3

Step-by-step explanation:

The Domain is the x values the function holds, while the range is the y values the function holds. This means that, looking at the graph, the range of the function is all y values less than or equal to 3, or Y ≤ 3.

You might be interested in

What is the relationship between fractions and decimals?

Tanzania [10]

The relationship between fractions and decimals is that with a fraction you are dividing whereas a decimal is treated like a number.
i.e. 1/4=0.25
Think of decimals as 100 being the whole or 1 so split 100 into 4 and you get 25 or 0.25

4 0

3 years ago

The expression 3 × 7 – 4 × 8 + 2 is equivalent

vlabodo [156]

I believe the answer you are looking for is -9<span />

3 0

2 years ago

Read 2 more answers

For her phone service, Kala pays a monthly fee of $24, and she pays an additional $0.07 per minute of use. The least she has bee

BartSMP [9]

Answer:

m=1352

Step-by-step explanation:

(118.64-24)/0.07=m

6 0

2 years ago

The coordinates A(2, 1), B(7, 1), C(2, 4) form what type of polygon?

Digiron [165]

Step-by-step explanation:

$Slope \: of \: AB = \frac{1 - 1}{7 - 2} = \frac{0}{5} = 0 \\ \\ Slope \: of \: BC = \frac{4 - 1}{2 - 7} = \frac{3}{ - 5} = - \frac{3}{ 5} \\ \\ \because \: Slope \: of \: AB \neq \: Slope \: of \: BC \\ \\ \therefore \: given \: points \: are \: non - collinear. \\$

Hence, coordinates A(2, 1), B(7, 1), C(2, 4) form a triangle.

6 0

3 years ago

Read 2 more answers

If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____

Sauron [17]

<h2>Answer:</h2>

$2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}$

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

$\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)$

So we need to find two things:

$2\vec{v}-6\vec{u}$

and:

$||2\vec{v}-6\vec{u}||$

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

$2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}$

SECOND:

If we name:

$\vec{w}=2\vec{v}-6\vec{u}$

Then, $||2\vec{v}-6\vec{u}||$ is the magnitude of the vector $\vec{w}$ . Therefore:

$||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}$

5 0

2 years ago

Read 2 more answers