Answer:
Step-by-step explanation:
We are given with two equations
first equation is 
second equation is
we find the result of subtracting two equation
subtract the second equation from the first, so
first equation - second equation, multiply second equation by -1 and then add it with first equation
Now add both equations, we get
For this case, what you should see is which lines contain point O.
We have then that the lines that contain this point are:
EC
AD
BO
We note that three lines contain point O.
Therefore, three lines intersect at the same point.
Answer:
4. 3
The answer is 3. This is because the perimeter is 30 so 5x+5x+x-3+x-3 = 30. Thus you have 12x-6=30 so x = 3
You have the correct answer. It is choice A. Nice work.
I prefer using full circles because sometimes the arcs could be too small in measure to not go where you want them to. If you're worried about things getting too cluttered (a legitimate concern), then I recommend drawing everything in pencil and only doing the circles as faint lines you can erase later. Once the construction is complete, you would go over the stuff you want to keep with a darker pencil, pen or marker. You can also use the circle as a way to trace over an arc if needed.
Choice B is false as a full circle can be constructed with a compass. Simply rotate the compass a full 360 degrees. Any arc is a fractional portion of a circle.
Choice C is false for similar reasoning as choice B, and what I mentioned in the paragraph above.
Choice D contradicts choice A, so we can rule it out. Arcs are easier to draw since it takes less time/energy to rotate only a portion of 360 degrees. Also, as mentioned earlier, having many full circles tend to clutter things up.
Answer:
Step-by-step explanation:
Rate X Time = distance
Therefore:
r (rate) X 5 (hours) = 600 (distance)
r = 600/5
r = 120 miles per hour
The rate of speed of the jet is 120 mph.
Then, to find out the distance flown in 13 hours:
120 (rate) X 13 (time) = d (distance)
120 X 13 = d
1560 = d
The distance flown in 13 hours is 1560 miles.
