Answer:
Step-by-step explanation
Hello!
Be X: SAT scores of students attending college.
The population mean is μ= 1150 and the standard deviation σ= 150
The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.
If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:
H₀: μ = 1150
H₁: μ ≠ 1150
α: 0.05
![Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)](https://tex.z-dn.net/?f=Z%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BSigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~~N%280%3B1%29)

The p-value for this test is 0.0949
Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.
I hope it helps!
175000 / 100 = 1750 this step finds 1% of 175000
1750 x 4.5 = 7875 this step finds 4.5% of 175000
Commission for first house $7875
199000 / 100 = 1990 this step finds 1% of 199000
1990 x 4.5 = 8955 this step finds 4.5% of 199000
Commission for second house $8955
$7875 + $8955 = $16,830
Kensho's commission for this quarter is $16,830
Answer:
07:45 or 7:45
Step-by-step explanation:
On a clock, the shorter hand shows the hour of the day, while the longer hand shows the minute. The clock is divided into 12 hours and 60 minutes. In this case, the shorter hand is between 7 and 8, and the minute hand is right at 45, meaning that the time is 07:45. Hope this helps!