Yes if you would like them to be considered that way depending on you x axis degree
Answer:
95% confidence interval for the variance of the bowling ball weight is between a lower limit of 13.328 pounds and an upper limit of 14.672 pounds.
Step-by-step explanation:
Confidence interval is given as weight +/- margin of error (E)
weight = 14 pounds
sample sd = 0.94 pound
n = 10
degree of freedom = n - 1 = 10 - 1 = 9
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (t) corresponding to 9 degrees of freedom and 5% significance level is 2.262
E = t × sample sd/√n = 2.262×0.94/√10 = 0.672 pounds
Lower limit of weight = weight - E = 14 - 0.672 = 13.328 pounds
Upper limit of weight = weight + E = 14 + 0.672 = 14.672 pounds.
95% confidence interval is (13.328, 14.672)
It is shifted five to the right
1/2 x^3 + 3.4y when x = 4 and y = 2
1/2(4)^3 + 3.4(2)
1/2 (64) + 6.8
32 + 6.8 = 38.8
