All categories

3 years ago

(1+v)(v-7) i need help to solve this question

1 answer:

kramer3 years ago

4 0

(1 + v)(v - 7)

1*(v - 7) + v(v - 7)

1*v - 1*7 + v*v - v*7

v - 7 + v² - 7v

v² - 7v + v - 7

v² - 6v - 7

I hope this helps.

You might be interested in

Y= x +2<br> x^2 +y^2=10<br><br> solve using any method

Jobisdone [24]

Hi there!

»»————-　★　————-««

I believe your answer is:

(-3, -1) and (1, 3)

»»————-　★　————-««

Here’s why:

I have graphed the two equations given on a graphing program.
When graphed, they pass at points (-3, -1) and (1,3). Therefore, they are the solutions to the system.

⸻⸻⸻⸻

See the graph attached.

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

7 0

3 years ago

Read 2 more answers

Assume that 6 people, including. the husband and wife pair, apply for 5 sales positions. People are hired at random. What is the

Dvinal [7]

Probability that one is hired ans one not:
P ( A ) = (2 C 1 * 4 C 4) / 6 C 5 =
= ( 2 * 1 ) / 6 = 2/9 = 1 / 3
Answer: 1/3 or 33.33%

7 0

3 years ago

35% of the students at charles drew middle school are 6th graders if there are 84 sixth graders what is the total number of stud

Juliette [100K]

Answer: The total number of student in the school = 240.

Step-by-step explanation:

Let x be the total number of students in the school.

Given: 35% of the students at Charles drew middle school are 6th graders.

i.e. Number of sixth graders = 35% of x = 0.35x [35% = 0.35]

Since there are 84 sixth graders in the school,

So $0.35x=84$

Divide both sides by 0.35, we get

$x=\dfrac{84}{0.35}=\dfrac{84\times100}{35}=240$

Hence, the total number of student in the school = 240.

6 0

3 years ago

Use the law of cosines to write an expression equivalent to b

andrezito [222]

Given:

A triangle ABC.

The given expression for b is:

$b=\sqrt{m+n-pq}$

To find:

The expression that is equivalent to b.

Solution:

According to the Law of Cosines,

$b^2=a^2+c^2-2ac\cos B$

It can be written as:

$b=\sqrt{a^2+c^2-2ac\cos B}$ ...(i)

We have,

$b=\sqrt{m+n-pq}$ ...(ii)

On comparing (i) and (ii), we get

$m=a^2$

$n=c^2$

$p=2ac$

$q=\cos B$

Therefore, the required values are $m=a^2,n=c^2,p=2ac,q=\cos B$ .

3 0

3 years ago

23,710 23,751,23,715

Hoochie [10]

23, 710, 23, 751, 23, 715 Least to greatest

23, 23, 23, 710, 715, 751

7 0

3 years ago