Answer: Option D
Step-by-step explanation:
Soup : 15/5 is 3 x 7 is 21
Peanut: 35/7 is 5 x 5 is 25
Answer:
![\sqrt{5}\cdot\sqrt[3]{5} =\sqrt[6]{5^3} \cdot\sqrt[6]{5^2} =\sqrt[6]{5^5} =5^{(5/6)}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D%5Ccdot%5Csqrt%5B3%5D%7B5%7D%20%3D%5Csqrt%5B6%5D%7B5%5E3%7D%20%5Ccdot%5Csqrt%5B6%5D%7B5%5E2%7D%20%3D%5Csqrt%5B6%5D%7B5%5E5%7D%20%3D5%5E%7B%285%2F6%29%7D)
Step-by-step explanation:
The rules of exponents apply, even when they are fractional exponents:
![a^b\cdot a^c=a^{b+c}\\\\\sqrt[b]{x^a}=x^{(a/b)}](https://tex.z-dn.net/?f=a%5Eb%5Ccdot%20a%5Ec%3Da%5E%7Bb%2Bc%7D%5C%5C%5C%5C%5Csqrt%5Bb%5D%7Bx%5Ea%7D%3Dx%5E%7B%28a%2Fb%29%7D)
Answer:
its A
Step-by-step explanation:
Hope it helps
Answer:
a) 0.0167
b) 0
c) 5.948
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 6.16 ounces
Standard Deviation, σ = 0.08 ounces
We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.
Formula:
a) Standard deviation of 23 bags

b) P( fill volume of 23 bags is below 5.95 ounces)
P(x < 5.95)
Calculation the value from standard normal z table, we have,
c) P( fill volume of 23 bags is below 6 ounces) = 0.001
P(x < 6) = 0.001
Calculation the value from standard normal z table, we have,


If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.
Answer:
3x+y
Step-by-step explanation:
It's already in simplest form, you can't do anything else to it.