If it reaches its maximum height a t=3 its velocity must be zero at t=3
dy/dx=0 at t=3
dA/dx=4x+12=24 at t=3 so this does not apply
dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies
dC/dx=-4x-12=-24 at t=3 so this does not apply
dD/dx=-4x-12=-24 at t=3 so this does not apply
dE/dx=-4x-12=-24 at t=3 so this does not apply
So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
<u> 70</u> =<u>63</u><u>
</u>100 ?
cross multiply 63 and 100= 6300 then divide by 70= 90
Answer:
8(15-m)
Step-by-step explanation:
By looking at the options, we can understand that the right one is 8(15-m), since we need to multiply the time by the number of question.
Also, we can check that result by arranging an equations usint the total time.
55 = 3m - 8(15-m)
55 = 3m - 120 + 8m
55 = 11m - 120
55 + 120 = 11m
175 = 11m
m = 175/11 = 15.91
55 = 3*15.91 - 8(15-15.91) = 47.73 - 120 + 127.28 = 55.01 ≈ 55
Let's see....
Let's first simplify step-by-step.
2/4 - 8z + 2(2-5)
= 1/2 + - 8z + -6
Combine Like Terms:
= 1/2 + -6
= (- 8z) + (1/2 + -6)
=(- 8z) + (1/2 + -6)
= - 8z + -11/2
___________________________________
Our answer:
= - 8z + -11/2
Hope This Helps!!!!!!!!
A part of a line that connects two endpoints I believe
