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Ksivusya [100]
3 years ago
15

I need Help on this one

Mathematics
2 answers:
ycow [4]3 years ago
7 0

Answer:

I believe the answer is x=7

Step-by-step explanation:

elixir [45]3 years ago
5 0
The answer is
X=7
Have a nice day <3
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In a high school, 7% of the students play the piano. This is 21 students. Choose the expressions that complete each step involve
Gnesinka [82]

Hello,

<u>Set up a proportion</u> :

7 → 21

100 → ?

<u>Cross multiply</u> :

100 * 21 / 7 = 300 students

Bye :)

7 0
3 years ago
−2x + 2y = −5 <br> 5x − 6y = 8
larisa86 [58]

Answer:

y= 5x/6-4/3     y=x-5/2      

Step-by-step explanation:

4 0
3 years ago
Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

8 0
3 years ago
The list below shows the results of a survey of favorite ice-cream flavors among middle-school students.
Mrac [35]

Answer:

40%

Step-by-step explanation:

18+12+20=50

20/50×100=

40%

8 0
3 years ago
A train is 300 meters long. A tunnel is 2900 meters long. The train travels at 600 meters per min. How long is the time between
sattari [20]

ANSWER: 5 minutes 20 seconds

WORK: entire train to get out of tunnel - 2900+300 = 3200 meters till it's out

at 600 meters per minute ...3200/600 = 5 1/3 = 1/3 of a minutes is 20 seconds

Hope this helps brainliest and rate/thanks helps!

8 0
3 years ago
Read 2 more answers
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