50 as 1 in the ratio
50:200
50 as 4 in the ratio
50:12.5
hope this helps
Answer:
15 units
Step-by-step explanation:
K(8, 6) and J(-4, -3)
Distance between 2 points

Thus using the formula above,
distance between points J and K
![= \sqrt{ {[8- (-4)]}^{2} + {[6- (-3)]}^{2} } \\ = \sqrt{ {12}^{2} + {9}^{2} } \\ = \sqrt{225} \\ = 15 \: units](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%5B8-%20%28-4%29%5D%7D%5E%7B2%7D%20%20%2B%20%20%7B%5B6-%20%28-3%29%5D%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%20%7B12%7D%5E%7B2%7D%20%20%2B%20%20%7B9%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B225%7D%20%20%5C%5C%20%20%3D%2015%20%5C%3A%20units)
Answer:
It is a right triangle, the right angle is at the point (-3, 5)
Step-by-step explanation:
The first step is to locate the points of the vertices in a plane, in this case they are (0.10), (-8.8) and (-3.5). The desmostration of this is shown in the attached image.
As we can see it is formed a right triangle (the figure outlined in red), and the rigth angle is the one at the point (-3,5).
The numbers are 6 and 5 because 6-5=1 and 6^2=36 or 6*6=36,5^2=25 or 5*5=25. 36+25=61