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3 years ago

Write an expression for the difference between 10 and x

Mathematics

1 answer:

Flauer [41]3 years ago

8 0

The expression is 10-x=

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Solve prt for t if i=105 p=700 r=0.05

Illusion [34]

I = prt
t = I/pr = 105/(700 x 0.05) = 105/35 = 3

Therefore, t = 3.

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3 years ago

3. A recipe calls for cups of flour, cup of white sugar, and cup of brown sugar.

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation: You just draw a line that is long enough for your question its that simple

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3 years ago

Alex has 3,330 toothpicks . He wants to use them all to make a floor mat with 18 equal rows . How many toothpicks should Alex us

Rudik [331]

Answer:

Step-by-step explanation:

for this problem we have to

3330/18=185 toothpicks for each row

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3 years ago

Read 2 more answers

in march, veronica walked 12 miles every day. in april, she increased her daily walking distance by 10%, in may, she added 10% t

masya89 [10]

First, find what 110% of 12 is by multiplying 12 by 1.1 (13.2).

Second, find what 110% of 13.2 is by multiplying 13.2 by 1.1 (14.52).

The answer is 14.52 miles each day in May.

I hope that this helps you.

6 0

3 years ago

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago