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bonufazy [111]
3 years ago
14

What is 5 divided 437 how do you write the problem

Mathematics
1 answer:
nika2105 [10]3 years ago
8 0

U can write it as:5/437=0.01144164759

Or:5÷437=0.01144164759


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if an exterior angle of a triangle has a measure of 35 degrees, what is the measure of the adjacent interior angle?
Alona [7]

Answer:

145

Step-by-step explanation:

Adjacent interior angle = x

Sum of exterior angle and adjacent interior angle = 180

35 + x = 180

x = 180 - 35

x = 145

3 0
3 years ago
Read 2 more answers
Can you help me plzs
Jlenok [28]

Answer:

164

Step-by-step explanation:

2x+7+5x+12=180

7x+19=180

7x+180-19

7x=171

----  ----

7      7

x=164

6 0
3 years ago
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Solve formula please
fiasKO [112]

c=PI*d

divide both sides by PI to get d by itself

d = c/PI

6 0
3 years ago
PLEASE HELP!!! Solve for y.
ivolga24 [154]
- 2.1 = y/6 + 17.1
- 2.1 - 17.1 = y/6
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So y = - 115.2.

Hope this helps ! This "/" is a fraction.

Photon
5 0
3 years ago
Write a coordinate proof to prove that the segment that joins the vertex angle of an isosceles triangle to the midpoint of its b
Natalija [7]

Answer:

Slope of the base segment line is zero, hence base segment is horizontal

Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical

Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base

Step-by-step explanation:

Here we prove the required relation as follows;

Let the isosceles be ABC

The coordinates of the points are

C = (0, 0) (Vertex)

A =  (-a, b)

C = (a, b)

P = (0, b) (Midpoint of base)

Therefore, the gradient or slope of the base AC is presented as follows;

Slope, m \, of \. base, \, AC= \frac{dy}{dx}  = \frac{b - b}{a - (-a)}  = \frac{0}{2\cdot a} = 0

Hence, segment AC is vertical

Slope, m \, of \, segment \ CP \,  joining \, vertex, \, to \, midpoint, P, on  \,AC = \frac{0 - b}{0 - 0}  = \frac{-b}{0} = Undifined.

Hence, segment CP is vertical

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base.

6 0
3 years ago
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