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4 years ago

What is bigger 9/2 or 8/3?

1 answer:

7 0

9/2 would be bigger than other 8/3

'cause we can either calculate it or can predict by the difference between numerator & denominator.

Hope it helped!

You might be interested in

The Schwartz family spent a total of $111.75 for Internet service for 3 months. Each month they received $5.50 as a credit on th

Alexus [3.1K]

Answer:

3 (x + 5.50) = 111.75; the monthly Internet service is $31.75

Step-by-step explanation:

Let

x = monthly cost of internet service

Each month they received $5.50 as a credit on the bill.

The Schwartz family spent a total of $111.75 for Internet service for 3 months.

Total cost of internet service for three months = 3(x + 5.550)

111.75 = 3(x + 5.50)

111.75 = 3x + 16.50

111.75 - 16.50 = 3x

95.25 = 3x

x = 95.25 / 3

= 31.75

x = $31.75

4 0

3 years ago

Read 2 more answers

Need help please 9× > 108

butalik [34]

Answer:

x > 12

Step-by-step explanation:

9x>108

x> 108/9

x > 12

8 0

3 years ago

Read 2 more answers

Can some one help me with this

pychu [463]

Answer:

Actually i don't know what is the wanted but now

i will find the total of the teenagers.

Step-by-step explanation:

$\frac{4000}{45\%} = \frac{x}{100\%} \\ x = \frac{4000 \times 100}{45} \\ x = 8889 \: \: teenagers$

I hope that is useful for you :)

6 0

3 years ago

Read 2 more answers

Help!!!! How do u do #13

alisha [4.7K]

The answer is 288cm

Hope this helps!

7 0

3 years ago

Read 2 more answers

A Square has the vertices at (-2,6) (6,1) (1,-7) (-7,-2). At what point do the diagonals of the square intercect

DerKrebs [107]

Answer: At point ( $-\frac{1}{2},-\frac{1}{2}$ )

Step-by-step explanation: <u>Diagonal</u> is a line uniting two opposite points. In a square, the diagonals intersect in a 90° and bisect each other, i.e., divides each diagonal into two segments of the same length.

In other words, the diagonals of a square meet at their midpoint, which is found as the following:

(x,y) = $(\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2})$

The opposite vertices of the given square are (-2,6) and (1,-7).

So, the intersection is

(x,y) = $(\frac{-2+1}{2} ,\frac{6-7}{2})$

(x,y) = $(-\frac{1}{2},-\frac{1}{2} )$

The diagonals of square with vertices (-2,6)(6,1)(1,-7)(-7,-2) intersect at point $(-\frac{1}{2},-\frac{1}{2} )$ .

4 0

3 years ago