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uranmaximum [27]
3 years ago
7

Line L is tangent to a circle whose center is at (3,2). If the point of tangency is (6,6) what is the slope of line L?

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer:

Slope of the line L will be -\frac{3}{4}

Step-by-step explanation:

We will use the theorem that tangent to a circle is always perpendicular to the radius joining center of the circle and point of tangency.

Let m_{1} is the slope of line joining center of the circle (3, 2) and point of tangency (6, 6).

And m_{2} is the slope of line L.

Then by the fact given above m_{1}\times m_{2}=-1-----(1)

Now m_{1}=\frac{y-y'}{x-x'}

m_{1}=\frac{6-2}{6-3}

m_{1}=\frac{4}{3}

Now from the equation 1

\frac{4}{3}\times m_{2}=-1

m_{2}=-\frac{3}{4}

Therefore, slope of the line L will be -\frac{3}{4}

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(a+200)÷400=2 тендеу ​
Oksana_A [137]

Answer: a=600

Step-by-step explanation:

(a+200)/400=2

a+200=2×400=800 so

a+200=800

a=600 because 800-200=600

Hope this helps. Stay healthy and safe and have a blessed and wonderful day and I hope you had a good Easter!

- Cutiepatutie

5 0
3 years ago
Read 2 more answers
What is the slope of the table x= 2, 0, -2, -4 y= 6, 1, -4, -9
Murrr4er [49]

Answer:

The slope of the table is m=\frac{5}{2}   or  m=2.5

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the following ordered pairs

(2,6),(0,1),(-2,-4) and (-4,-9)

take two points

(2,6) and (-4,-9)

substitute in the formula

m=\frac{-9-6}{-4-2}

m=\frac{-15}{-6}

simplify

m=\frac{5}{2}

6 0
3 years ago
In triangle ABC, (angle A) is a right angle and (m angle B) = 45deg.
Ratling [72]
We can use the ratios for special triangles (see the attachment below). We'll be using the 45-45-90 triangle. We notice that side BC is equal to x \sqrt{2}, and side AC (x using the special right triangle) is equal to 16. We can therefore say that side BC is equal to 16 \sqrt{2} ft

:)

4 0
3 years ago
Read 2 more answers
**60 PTS**
IgorC [24]
A. It is an experiment as the sales director is applying treatment ( the training ) to a group and recording the results.

B. I would have 250 sales representatives from each region take the training and 250 from each region to not take it so i can be able to see if it affects both regions differently. The representatives from each region would be chosen at random and the length of their training would be the same for all.

C. now you would only be able to have 200 people from each region train. this would lower the percentage of the impact the training had on the amount of sales ( if any) . For example, if the original 250 trained people in a region increased the sales in that region by 20 percent and 50 of those people ended up not actually training, the sales would have only increased by 16 percent.

D. correlational research is best to establish causality. for example, the amount of training the representatives got may affect how much they are able to sell. also the number of representatives trained may affect the amount sold
3 0
3 years ago
Picture attached with question
Mariana [72]

The function is stretched vertically by a factor of 3.

The function shifts 2 to the right.

The function is moved 5 units up.

Explanation:

The parent function of the graph is f(x)=\sqrt{x}

The transformation for the parent function is given by g(x)=3\sqrt{x-2} +5

Thus, the transformed function is in the form of y=a\sqrt{x-h} +k

where a is the vertical compression/stretch,

h moves graph to left or right and

k moves the graph up or down.

Thus, from the transformed function g(x)=3\sqrt{x-2} +5, we have,

a=3, h=2 , k=5

The attached graph below shows the transformation of the graph that the graph is stretched vertically by a factor of 3 and shifted 2 units to the right and moved 5 units up.

Hence, The function is stretched vertically by a factor of 3.

The function shifts 2 to the right.

The function is moved 5 units up.

6 0
3 years ago
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