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4 years ago

6

the large Square above has area 9 is divided into 9 smaller squares of equal area what is the length of how strong and bold

1 answer:

Kay [80]4 years ago

8 0

If one square is divided into 9 smaller equal squares, then they have to be arranged in 3 lines of 3, that is 3 smaller equal squares per side of the original big square. That said, the area of the big square is equal to the multiplication of 3 small squares sides times 3 small squares sides, call x the length of the small squares.
So,
area = 9 = 3x*3x
9x^2 = 9
x^2 = 1
x = 1
therefore the smaller squares have sides of 1 unit

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Step-by-step explanation:

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3 years ago

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Simora [160]

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Step-by-step explanation:

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3 years ago

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vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

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Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

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a = 9

Verifying :

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$b^2 = 117$

$b^{2}$ = 117

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$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

8 0

3 years ago