v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Answer:
Michael is running for president. The proportion of voters who favor him is 0.3. A simple random sample of 100 voters is taken.
a)
What is the expected value :: n*p = 100*0.8 = 80
standard deviation:: sqrt(n*p*q) = sqrt(80*0.2) = 16
where q is proportion of voters who do not favor Michael. (q=0.2)
and shape of the sampling distribution is binomial distribution which is approximately a bell shaped.
-------------------------
what is the probability that the number of voters in the sample who will not favor Michael will be more than 16
P(X < 16.0) = P((x - 20) / 4.0) < (16.0 - 20) / 4.0) = P(Z < -1.00) = .1587
P(X > 16.0) = 1 - 0.1587 = 0.8413
Answer: The cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.
Step-by-step explanation:
Let x be the cost of one sandwich and y be the cost of one cup of coffee.
By considering the given situation, we have the following equations :-

Multiply 2 on both sides of equation (2) , we get

Subtract equation (1) from equation (3), we get

Put value of y in (1), we get

Hence, the cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.
Answer:
EBC = 90
FBG = 25
ABF = 115
ABG = 140
EBG = 50
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