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kherson [118]
3 years ago
7

60 POINTS PLS HELP!!

Mathematics
2 answers:
Nadya [2.5K]3 years ago
8 0

Answer:

Solution given:

single positive exponent

\frac{8^{3} }{8}=8^{3-1}=8²

<u>single positive </u><u>exponent</u><u> </u><u>i</u><u>s</u><u> </u><u>8</u><u>²</u><u>.</u>

<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u>

<u>w</u><u>e</u><u> </u><u>h</u><u>a</u><u>v</u><u>e</u><u> </u>

\frac{x^{a}}{x^{b}}=x^{a-b}

-Dominant- [34]3 years ago
6 0

Answer:

it is 8^2.

Step-by-step explanation:

8 ^ 3 = 8 x 8 x 8

8^3/8 = 8 x 8 x 8 / 8

you cross one 8 on the bottom and the top which leaves you with 8 x 8 or 8^2

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A triangular field has sides 218.5 and 213.3 and the angle between them measures 58.96°. Find the area of the field.
Zolol [24]

Answer:

The area of the field = 19966.21 units²

Step-by-step explanation:

* Lets explain how to find area of a triangle by trigonometry rule

- In any triangle if you have the lengths of two sides and the measure

 of the including angle between these two sides, then the area of the

 triangle is A = \frac{1}{2}s_{1}s_{2}sin\alpha , wher α is the

 including angle between them

* Lets solve the problem

∵ The field is shaped triangle

∵ The lengths of two sides of the field are 218.5 and 213.3

∴ s1 = 218.5

∴ s2 = 213.3

∵ The measure of the angle between the two sides is 58.96°

∴ α = 58.96°

- Lets find the area using the rule of trigonometry

∴ A=\frac{1}{2}(218.5)(213.3)sin(58.96)=19966.21

∴ The area of the field = 19966.21 units²

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Read 2 more answers
What does sec 2pi equal?
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I need help with this question
AlexFokin [52]
A
Find the two intersections of the lines. The value of x of the intersections will satisfy the system of equations.
Brainliest pls!
3 0
2 years ago
PLEASE HELP!! URGENT!! i will mark brainliest if its right!! In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and DF ≅ BD. Point C is
zvonat [6]

Answer:

See below.

Step-by-step explanation:

This is how you prove it.

<B and <F are given as congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

<DEC and <DCE are given as congruent.

Using vertical angles and substitution of transitivity of congruence of angles, show that angles ACB and GEF are congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

Now you need another side to do either AAS or ASA.

Look at triangle DCE. Using the fact that angles DEC and DCE are congruent, opposite sides are congruent, so segments DC and DE are congruent. You are told segments DF and BD are congruent. Using segment addition postulate and substitution, show that segments CB and EF are congruent.

Now you have 1 pair of included sides congruent ABC and GFE.

Now using ASA, you prove triangles ABC and GFE congruent.

7 0
3 years ago
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