How many area codes (ABC) would possible if all three could be any value 1-9?

1 answer:

Leni [432]3 years ago

3 0

1-9 = 9 numbers

so you have 9 *9 *9 = 729 different codes

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valentinak56 [21]

Answer: 17/24
Eplination: you need a common demonator

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3 years ago

Dmitry_Shevchenko [17]

Answer:

288

Step-by-step explanation:

the formula is 2(lw+wh+hl)

length - 8

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substitute the values and you get

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3 years ago

deff fn [24]

The answer is:
D.90
I hope I helped

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3 years ago

mario62 [17]

The answer is B) Translation, Congruent

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3 years ago

loris [4]

Answer:

$g(2) = 4(2) - 5 \\ = 8 - 5 \\ = 3 \\ \\ g( - 4) = 4( - 4) - 5 \\ = - 16 - 5 \\ = - 21$

The answer is A

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3 years ago