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Inessa05 [86]
3 years ago
10

In the equation above,a,b, and c are constants. If the equation is true for all values of x, what is the value of b?

Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0
Hope this answer helps.

oksano4ka [1.4K]3 years ago
4 0

Answer:

b=19

Step-by-step explanation:

We are given that an equation

2x(3x+5)+3(3x+5)=ax^2+bx+c

Given that the equation is true for all x

We have to find the value of b

2x(3x+5)+3(3x+5)=ax^2+bx+c

6x^2+10x+9x+15=ax^2+bx+c

6x^2+19x+15=ax^2+bx+c

Comparing coefficients of x^2 xand constant value  on both side then we get

a=6,b=19,c=15

Hence, the value of b=19

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Shtirlitz [24]

Answer:

The endpoints of the latus rectum are (12, -7) and (-8, -7).

Step-by-step explanation:

A parabola with vertex at point C(x, y) = (h,k) and whose axis of symmetry is parallel to the y-axis is defined by the following formula:

(x-h)^{2} = 4\cdot p \cdot (y-k) (1)

Where:

y - Independent variable.

x - Dependent variable.

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The coordinates of the focus are represented by:

F(x,y) = (h, k+p) (2)

The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that h = 2, k = -2 and p = -5, then the latus rectum is between the following endpoints:

By (2):

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F(x,y) = (2,-7)

By (1):

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There are two solutions:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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