Question

In the equation above,a,b, and c are constants. If the equation is true for all values of x, what is the value of b?

Answer 1

Hope this answer helps.

Answer 2

Answer:

b=19

Step-by-step explanation:

We are given that an equation

$2x(3x+5)+3(3x+5)=ax^2+bx+c$

Given that the equation is true for all x

We have to find the value of b

$2x(3x+5)+3(3x+5)=ax^2+bx+c$

$6x^2+10x+9x+15=ax^2+bx+c$

$6x^2+19x+15=ax^2+bx+c$

Comparing coefficients of $x^2$ xand constant value  on both side then we get

$a=6,b=19,c=15$

Hence, the value of b=19