Answer:
Hi mate your answer is
Step-by-step explanation:
Area of traingle equal 1/2×base×height
We have divided by two this is because you know the are of a rectangle is base + height but a triangle is like cut rectangle into two half pieces of you look carefully than to make any traingle a rectangle you will have to take another on opposite side so that's why we divide it by two
If you need further help plz ask
Answer:
Step-by-step explanation:
We are given the equation 
. To find y-value when or at x = 3, simply substitute x = 3 in which gives us 
then evaluate the value as we obtain the y-value or final answer to the question:
If you have any questions about this question or for clarification, do not hesitate to ask in comment!
Answer:
y=1/3x+0 or y=1/3x
Step-by-step explanation:
find the slope by taking two points and putting them in
y2 - y1/x2 - x1
so, (3,1) and (6,2) becomes 2-1/6-3 or 1/3 so, slope is 1/3
then to find y intercept you can put a point (6,2) and slope (1/3) into slope intercept form y - y1 = m(x - x1)
y - 2 = 1/3(x-6)
when you solve this you get y = 1/3x + 0, so y intercept is 0. you can also see. this on the graph given
Answer:
Step-by-step explanation:
find the composition of g(x)=x−1 and h(x)=
hence we will get,
(g∘h)(x)=g(h(x))= g(x−1)= f(√x)= -1+√x = √x -1
Now to find f(g(h(x))),
f(x)=x4+6 and g(h(x))=√x -1
hence , putt g(h(x)) in f(x) ,
f(g(h(x)))=
+6 -
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Answer:
a) The very first one where the line starts to the left
b) m=125.82
c) 320.81 thousand dollars
Step-by-step explanation:
a) The point on the graph who corresponds to x=3 years and Salary=$200,000 is the very first one where the line starts to the left
b) If a line is given by Y=mx+b, m represents the slope of the line. In this case, m=125.82 which can be interpreted as the rate of growth of the salary per year in thousands of dollars. A doctor can expect to earn 125.82 thousand dollars more than the previous year.
c) If we use the given regression line Y=125.82x-182.47 and make x=4, we get
y=125.82 (4)-182.47 =320.81 thousand dollars
