3 years ago

What is the length of the third side of the window frame below?

Mathematics

1 answer:

Nostrana [21]3 years ago

8 0

Answer:

C 40 inches

Step-by-step explanation:

You can use the pythagorean theorem to solve for the second leg. When you plug in 42 for a and 58 for c, you get 42^2 + b^2 = 58^2, then you can isolate b, which should be 40 inches.

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What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?

yKpoI14uk [10]

$a_1=8$
$a_2=a_1+d=8+d$
$a_3=a_2+d=(8+d)+d=8+2d$
$a_4=a_3+d=(8+d)+2d=8+3d$
...
$a_9=8+8d=48\implies d=5$
$a_{10}=8+9d$
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$a_{23}=8+22d=118$

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3 years ago

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Given cos A = .23 find angle A in radians. Round your answer to the nearest hundredth.

irinina [24]

Use a calculator and change DEG (degres) to RAD (radians).

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3 years ago

Determine the kinetic energy of 8000 Newton’s roller coaster car that is moving with a speed of 20.0 meters/seconds

ohaa [14]

Answer:

The kinetic energy of the roller coaster is 1600000 J.

Step-by-step explanation:

Given:

Mass of the roller coaster is 8000 Newton's and speed 20.0 meters/seconds.

Now, we need to find the kinetic energy $E_{k}$ of the roller coaster.

So, Mass of roller coaster (m) = 8000 N.

Velocity of roller coaster (v) = 20.0 m/s.

Now, putting the formula of kinetic energy:

$E_{k} = \frac{1}{2}\times m\times v^{2}$

$E_{k}=\frac{1}{2} \times 8000\times 20^{2}$

$E_{k}=\frac{1}{2} \times 8000\times 400$

$E_{k}=\frac{1}{2} \times 3200000$

$E_{k}=1600000$

Therefore, the kinetic energy of the roller coaster is 1600000 J.

3 0

3 years ago

Jose invests $3,250 at 6% interest compounded annually. what will be the balance of the account after 3.5 years? A) $3,932.50 B)

tino4ka555 [31]

3250 + 3.5(3250 x 0.06) = 3250 + 682.5 = A) 3932.50

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3 years ago

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Which of the following numerical data sets has a mean of 40?

34kurt

Answer:

The answer is B) 21, 34, 65

Step-by-step explanation:

21 + 34 + 65 = 120

120 divided by 3 = 40.

In order to find the mean you must add up all of the numbers in the numerical data set, then divide that by how many numbers there are. Hope this helps! :)

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2 years ago