Answer:
sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)
Step-by-step explanation:
sec²(x) - sec(x) + tan²(x) =
= sec²(x) - sec(x) + [sec²(x) - 1]
= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]
= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]
= (sec(x) - 1)(sec(x) + sec(x) + 1)
= (sec(x) - 1)(2sec(x) + 1)
Answer:
OPtion B
Step by step explanation:
Lets plug in a random value for x.
Lets say 5 is x
-8(-5-5)=(y+1)^2
5-5 = 0
-8(0) = 0
0 = (y+1)^2
Square root of both sides
0 = y+1
subtract one from both sides
-1 = y
that means the x is 5 and the y is -1. Option B illustrates exactly that!
Answer:
Please find attached pdf
Step-by-step explanation: