Answer:
Future value of annuity (FV) = $13,782.12 (Approx)
Step-by-step explanation:
Given:
Periodic payment p = $500
Interest rate r = 13% = 13%/4 = 0.0325 (Quarterly)
Number of period n = 5 x 4 = 20 quarter
Find:
Future value of annuity (FV)
Computation:
![Future\ value\ of\ annuity\ (FV)=p[\frac{(1+r)^n-1}{r} ] \\\\Future\ value\ of\ annuity\ (FV)=500[\frac{(1+0.0325)^{20}-1}{0.0325} ] \\\\Future\ value\ of\ annuity\ (FV)=13,782.1219 \\\\](https://tex.z-dn.net/?f=Future%5C%20value%5C%20of%5C%20annuity%5C%20%28FV%29%3Dp%5B%5Cfrac%7B%281%2Br%29%5En-1%7D%7Br%7D%20%5D%20%5C%5C%5C%5CFuture%5C%20value%5C%20of%5C%20annuity%5C%20%28FV%29%3D500%5B%5Cfrac%7B%281%2B0.0325%29%5E%7B20%7D-1%7D%7B0.0325%7D%20%5D%20%5C%5C%5C%5CFuture%5C%20value%5C%20of%5C%20annuity%5C%20%28FV%29%3D13%2C782.1219%20%5C%5C%5C%5C)
Future value of annuity (FV) = $13,782.12 (Approx)
Answer:
-0.3
Step-by-step explanation:
i don't really have an explanation i just know
Let 'w' represent the width of the parking lot, then 'w+6' represents its length
area = width * length
160 = w * (w+6)
solving for 'w' we have a positive value of w=10
10+6=16
the width of the parking lot is 10 yards, the length of the parking lot is 16 yards
Answer:
The answer is 58.09
Step-by-step explanation:
To get the final position, you add the displacement to the initial position.
Final position = 25.89 + 32.2
Final position = 58.09metres
