He gave them $5 a day wagers
Answer:
b for the first one and A for the second
Step-by-step explanation:
Answer c I’m pretty sure
Step-by-step explanation:
Answer:
The probability that components #1 and #2 fail, and at least one of components #3 and #4 fails is 0.031875
Step-by-step explanation:
Let's define the following events,
F1: Component #1 fails
F2: Component #2 fails
F3: Component #3 fails
F4: Component #4 fails
We are looking for the following probability
P[(F1∩F2)∩(F3∪F4)]
using distributive laws we have
P[(F1∩F2)∩(F3∪F4)] = P[(F1∩F2∩F3)∪(F1∩F2∩F4)] = P(F1∩F2∩F3) + P(F1∩F2∩F4) - P(F1∩F2∩F3∩F4) = P(F1)P(F2)P(F3) + P(F1)P(F2)P(F4) - P(F1)P(F2)P(F3)P(F4) = (0.25)(0.25)(0.3) + (0.25)(0.25)(0.3) - (0.25)(0.25)(0.3)(0.3)=0.031875
by the assumption of independence (the components fail independently) and because P(F1) = P(F2) = 0.25, P(F3) = P(F4) = 0.3
Answer:
To tell if it is proportional, you have to see if they increase by the same amount each time. It is not the first one.
It is the second one.
It is the third one
It is not the 4th one
it is the 5th one
Step-by-step explanation:
