Answer:
a) 279 b)254
Step-by-step explanation:
Mean = 269 days
standard deviation = 8 days
let n be the pregnancy lenght.
using normal distribution formula
z = (n – mean)/ standard deviation
n = z * standard deviation + mean
Now, z values for the top 12% has to be found using a z table.
The top 12% means 88% of area under the curve. In this case z = 1,176
n = 1,176 * 8 + 269
n = 278.4 = 279
The bottom 3% means 97% of area under the curve. In this case z = -1,882
n = -1,882 * 8 + 269
n = 253.94 = 254
Decimal: 0.72
Fraction: 18/25
Answer:
The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Step-by-step explanation:
We are given that
Standard deviation,
ounces
We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

Assume the bag weight distribution is bell-shaped
Therefore,

We know that

Using the value of z
Now,




Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Lol I don’t understand that language
Answer:
(0,1) (0.333,0)
(7,0)
m=1
Step-by-step explanation: