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finlep [7]
3 years ago
6

40 cookies are in a jar. 1/5 of the cookies are chocolate cookies. Someone eats 1/4 of the chocolate cookies. How many cookies r

emain in the jar?​
Mathematics
1 answer:
pickupchik [31]3 years ago
5 0
6 cookies remain in the jar
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420÷14 show picture please
Andru [333]
14/420
14*3=42
14*0=0
Ur answer is 30
Prove
30*14=420
5 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through (3, 4) and ( 2, -1) in slope-intercept form
rjkz [21]

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{3}}}\implies \cfrac{-5}{-1}\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{5}(x-\stackrel{x_1}{3}) \\\\\\ y-4=5x-15\implies y=5x-11

3 0
3 years ago
Help me please that's problem number3 .help me
Firlakuza [10]

A) Both walked 3.5 hours.

B) Hannah walked 3.5 x 3 = 10.5 miles.

For Hannah you multiplied her rate by the time to get total distance.

Penelope walked 7 miles, the black dot on the graph is at the 7 miles on the distance.

C) Hannah walked a faster rate, because she walked further in the same amount of time.

5 0
2 years ago
Answer this Please (I will give you brainliest if you get it correct) <br>This is tree diagrams
s344n2d4d5 [400]

Answer:

18 combinations

Step-by-step explanation:

There are three chocolates and six different options to mix with those chocolates. Each chocolate has six different options. So, it comes to 6 + 6 + 6 or 6 • 3 whoch equals 18 different combinations.

7 0
2 years ago
Evaluate the line integral using the fundamental theorem of line integrals. use a computer algebra system to verify your results
mario62 [17]
\dfrac{\partial f}{\partial x}=\cos x\sin y\implies f(x,y)=\sin x\sin y+g(y)

\dfrac{\partial f}{\partial y}=\sin x\cos y=\sin x\cos y+\dfrac{\mathrm dg}{\mathrm dy}
\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C

f(x,y)=\sin x\sin y+C

\displaystyle\int_{\mathcal C}\cos x\sin y\,\mathrm dx+\sin x\cos y\,\mathrm dy=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(\frac{3\pi}2,\frac\pi2\right)-f(0,-\pi)=-1
7 0
3 years ago
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