This is an Arithmetic Progression with 1st term 11 and common difference d=6
Number of Rows Number of seats Common difference " d"
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1st a₁ = 11
2nd a₁+d =17 d =2nd - 1st = 6
3rd a₁ +2d = 23 d =3rd - 2nd = 6
4th a₁ +3d = 29 d= 4th - 3rd = 6
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nth ROW a(n) = a₁ + (n-1)d
18th ROW a₁₈ = 11 + (18-1).6 = 11+(17)(6) = 113
General equation to predict the number of seat an the nth row:
Number of seats in nth row = a₁ + (n-1).d
Answer:
Given that The data to represent average test scores for a class of 16 students includes an outlier value of 78.
We can find sum of all 16 test scores = 84(16) = 1344
Outlier found = 78
If outlier is removed new sum = 1344-78 = 1266
Number of entries without outlier = 15
New average = 1266/12 =84.4
We find that average of new data increases.
Also whenever we remove outlier std deviation also would be reduced.
Step-by-step explanation:
Answer:x=17 y=10
Step-by-step explanation: