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Olenka [21]
3 years ago
5

ray bought 5 lemons and 3 limes for $7.20. Lia bought 4 lemons and 6 limes for the same price. How much would it cost to buy 1 l

emon and 1 lime?
Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0
5x+3y=7.2--->-2(5x+3y)=7.2*-2--->-10x-6y=-14.4
4x+6y=7.2--->4x+6y=7.2------------>4x+6y=7.2

-6x=-7.2---->x=7.2/6 or 1.27
4(1.27)+6y=7.2---->5.08+6y=7.2----> 6y=2.12
y=.35
x=lemons  y=limes
erma4kov [3.2K]3 years ago
8 0

Answer: The cost of 1 lemon is $1.2 and the cost of 1 lime is $0.4.

Step-by-step explanation:

Let x be the cost of 1 lemon and y be the cost of 1 lime.

Then for Ray, the equation representing total price will be :-

5x+3y=7.20................................(1)

For Lia, the equation representing total price will be :-

4x+6y=7.20..................................(2)

Dividing 2 on the both sides of equation (2), we get

2x+3y=3.60...............................(3)

Subtracting (3) from (1), we get

3x=3.6\\\\\Rightarrow x=1.2

Substitute value of x in (3), we get

2(1.2)+3y=3.6\\\\\Rightarrow2.4+3y=3.6\\\\\Rightarrow3y=1.2\\\\\Rightarrow y=0.4

Thus, the cost of 1 lemon is $1.2 and the cost of 1 lime is $0.4.

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