Can someone plz answer these 3 questions 60pts.
2 answers:
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Answer:
12709 balls
Step-by-step explanation:
Given
Dimension of Room = 15 ft by 20 ft by 10 ft
Diameter of Ball = 9.2 inches
Required
Determine the number of balls that can be occupied by the room
First, we need to calculate the volume of the room
This is done by multiplying the dimensions of the room
Next, we calculate the volume of the ball.
The ball is a sphere.
So:
Where
So:
To calculate the number of balls, we then divide the volume of the room by volume of a ball
Convert ft^3 to in^3
<em>-- approximated</em>
<em>Hence, the room will contain 12709 balls</em>
Answer:
a). Yes. Area will be less than 100 square in.
b). Area of octagon = 82 in²
Step-by-step explanation:
From the picture attached,
a). Octagon is inscribed in a square having one side = 10 inches.
Since, octagon is obtained by cutting off the four equal corners of the square,
Area of octagon will be less than the area of the square.
Area of square = (side)²
= 10²
= 100 in²
Therefore, area of octagon will be less than 100 in²
b). Since, corner cut off from the square are equal in shape and area,
Area of one corner (right angle triangle) =
=
= 4.5 in²
Area of 4 corners = 4.5 × 4 = 18 in²
Area of octagon = Area of square - Area of 4 corners removed
= 100 - 18
= 82 in²
