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finlep [7]
4 years ago
13

Savannah is currently one more than twice the age of her cat, Selena Gomez. In thirteen years, Savannah will be 1.5 times as old

as Selena. What is Savannah's current age?
Mathematics
2 answers:
Reil [10]4 years ago
8 0
Uhh I believe the answer is 23
zaharov [31]4 years ago
5 0

Answer:

23 years old

Step-by-step explanation:

Savannah's age = x

Selena's age = y

Right now, x = 2y + 1

In 13 years, x = 1.5y

Here, we must use simultaneous equations to work it out.

x = 2y + 1

x + 13 = 1.5 x (y + 13)   --> x + 13 = 1.5y + 1.5 x 13   --> x + 13 = 1.5y + 19.5

x + 13 = 1.5y + 19.5

- 13

x = 1.5y + 6.5

x = 1.5y + 6.5 = 2y + 1

1.5y + 6.5 = 2y + 1

- 1

1.5y + 5.5 = 2y

- 1.5y

5.5 = 0.5y

x 2

11 = y

We know that y = 11

Savannah is currently twice her cat's age plus 1, so...

11 x 2 + 1 = 22 + 1 = 23 years old

Hope this helps!

P.S. If the cat lives 13 more years after this, it will be a very old cat lol :)

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Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that comput
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Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

P = C_{n,x}.p^{n}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

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And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so p = 0.53

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 0 successes, so x = 0.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{0}.(0.47)^{4}

P = 0.0488

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 4.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{4}.(0.47)^{0}

P = 0.0789

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 2.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,2}.(0.53)^{2}.(0.47)^{2}

P = 0.3723

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

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