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kherson [118]
3 years ago
8

How long will it take to travel 546 km at 110 km/hr (answer in hours)

Physics
1 answer:
Andre45 [30]3 years ago
3 0
(60 * 546) / 110 = 297

297 hrs.
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Which changes of state occur between solids and gases
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Between both solid and gases, should be liquid. 
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Niko was hiking in the mountains when he found a spring, or a place where water naturally flows out of the ground. Where did the
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it is from under the earth's surface. There are under the surface streams that create springs

It is precipitation that fell on the ground and seeped down to a layer of rock. The water comes from an aquifer that is under the ground.

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4 years ago
What is the wavelength of red light in vacuum that has a frequency of 4.00 × 1014 hz?
Pachacha [2.7K]

Answer: 7.5(10)^{-7} m

Explanation:

The frequency \nu of an electromagnetic wave is given by the following equation:  

\nu=\frac{c}{\lambda}  

Where:  

c=3(10)^{8} m/s is the speed of light  in vacuum

\nu=4(10)^{14} Hz is the frequency of red light

\lambda   is the wavelength of red light

Isolating \lambda:

\lambda=\frac{c}{\nu}  

\lambda=\frac{3(10)^{8} m/s}{4(10)^{14} Hz}  

Finally:

\lambda=7.5(10)^{-7} m  

6 0
4 years ago
Which method would be best to separate a mixture of iron and lead pellets (of the same approximate diameter)? magnetism screenin
KATRIN_1 [288]
Separation by density filtration because lead slightly interacts with magnets also.
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3 years ago
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Particle A of charge 3.06 10-4 C is at the origin, particle B of charge -5.70 10-4 C is at (4.00 m, 0), and particle C of charge
Alex

Answer:

F_net = 26.512 N

Explanation:

Given:

Q_a = 3.06 * 10^(-4 ) C

Q_b = -5.7 * 10^(-4 ) C

Q_c = 1.08 * 10^(-4 ) C

R_ac = 3 m

R_bc = sqrt (3^2 + 4^2) = 5m

k = 8.99 * 10^9

Coulomb's Law:

F_i = k * Q_i * Q_j / R_ij^2

Compute F_ac and F_bc :

F_ac = k * Q_a * Q_c / R^2_ac

F_ac =  8.99 * 10^9* ( 3.06 * 10^(-4 ))* (1.08 * 10^(-4 )) / 3^2

F_ac = 33.01128 N

F_bc = k * Q_b * Q_c / R^2_bc

F_bc =  8.99 * 10^9* ( 5.7 * 10^(-4 ))* (1.08 * 10^(-4 )) / 5^2  

F_bc = - 22.137 N

Angle a is subtended between F_bc and y axis @ C

cos(a) = 3 / 5

sin (a) = 4 / 5

Compute F_net:

F_net = sqrt (F_x ^2 + F_y ^2)

F_x = sum of forces in x direction:

F_x = F_bc*sin(a) = 22.137*(4/5) = 17.71 N

F_y = sum of forces in y direction:

F_y = - F_bc*cos(a) + F_ac = - 22.137*(3/5) + 33.01128 = 19.72908 N

F_net = sqrt (17.71 ^2 + 19.72908 ^2) = 26.5119 N

Answer: F_net = 26.512 N

5 0
4 years ago
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