How long will it take to travel 546 km at 110 km/hr (answer in hours)

uniform disk with mass 40.0 kg and radius 0.200 m is pivoted at its center about a horizontal, frictionless axle that is station

Alex787 [66]

Answer:

The magnitude of the tangential velocity is $v= 0.868 m/s$

The magnitude of the resultant acceleration at that point is $a = 4.057 m/s^2$

Explanation:

From the question we are told that

The mass of the uniform disk is $m_d = 40.0kg$

The radius of the uniform disk is $R_d = 0.200m$

The force applied on the disk is $F_d = 30.0N$

Generally the angular speed i mathematically represented as

$w = \sqrt{2 \alpha \theta}$

Where $\theta$ is the angular displacement given from the question as

$\theta = 0.2000 rev = 0.2000 rev * \frac{2 \pi \ rad }{1 rev}$

$=1.257\ rad$

$\alpha$ is the angular acceleration which is mathematically represented as

$\alpha = \frac{torque }{moment \ of \ inertia} = \frac{F_d * R_d}{I}$

The moment of inertial is mathematically represented as

$I = \frac{1}{2} m_dR^2_d$

Substituting values

$I = 0.5 * 40 * 0.200^2$

$= 0.8kg \cdot m^2$

Considering the equation for angular acceleration

$\alpha = \frac{torque }{moment \ of \ inertia} = \frac{F_d * R_d}{I}$

Substituting values

$\alph$ $\alpha = \frac{(30.0)(0.200)}{0.8}$

$= 7.5 rad/s^2$

Considering the equation for angular velocity

$w = \sqrt{2 \alpha \theta}$

Substituting values

$w =\sqrt{2 * (7.5) * 1.257}$

$= 4.34 \ rad/s$

The tangential velocity of a given point on the rim is mathematically represented as

$v = R_d w$

Substituting values

$= (0.200)(4.34)$

$v= 0.868 m/s$

The radial acceleration at hat point is mathematically represented as

$\alpha_r = \frac{v^2}{R}$

$= \frac{0.868^2}{0.200^2}$

$= 3.7699 \ m/s^2$

The tangential acceleration at that point is mathematically represented as

$\alpha _t = R \alpha$

Substituting values

$\alpha _t = (0.200) (7.5)$

$= 1.5 m/s^2$

The magnitude of resultant acceleration at that point is

$a = \sqrt{\alpha_r ^2+ \alpha_t^2 }$

Substituting values

$a = \sqrt{(3.7699)^2 + (1.5)^2}$

$a = 4.057 m/s^2$

7 0

3 years ago

The amount of dissolved oxygen in water may decrease because of the

Elanso [62]

<span>The amount of dissolved oxygen in water may decrease because of the increase in organic matter in the water. <span>Aquatic organisms breathe and use oxygen. Large amounts of oxygen are consumed by the decomposition of bacteria (when there are large amounts of dead matter to decompose, there will be a significant number of bacteria). Examples: dead organic matter (algae), wastewater, garden waste, oils and fats, all this results in a decrease in dissolved oxygen in the water.</span></span>

8 0

3 years ago

Read 2 more answers

M A spherical conductor has a radius of 14.0cm and a charge of 26.0σC . Calculate the electric field and the electric potential

Yuri [45]

The Electric field is E=23400 V/m.

What is electric potential ?

The amount of labor required to convey a unit of electric charge from a reference point to a given place in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential). More specifically, it is the energy per unit charge for a test charge that is negligibly disruptive to the field under discussion.

The electric field of a spherical conductor is given by:

$E={\frac {Q}{4\pi \varepsilon _{0}\,r^{2}}$

Here 'E' is the electric field and 'Q' is the electric charge.

therefore putting the values we get,

E=23400 V/m

To learn more about electric field click on the link below:

brainly.com/question/11509296

#SPJ4

4 0

2 years ago

The gravitational force between Earth and the Sun is a two-way force. Both the planet and the Sun attract each other. However, E

Ymorist [56]

The correct choice would be

B) The Sun’s mass is much greater than Earth’s

The sun as we know has greatest mass in our solar system and lighter objects tends to orbit around the heavier objects. the mass of earth is very much smaller as compared to that of the sun. hence the earth orbits around the sun due to the force of gravitational attraction between the two objects.

8 0

3 years ago

Read 2 more answers

A 0.145 kg baseball is thrown with a velocity of 25.0 m/s. How much work was done on the baseball to bring it from rest to 25.0

sergey [27]

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s