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Gemiola [76]
4 years ago
12

What is the wavelength of red light in vacuum that has a frequency of 4.00 × 1014 hz?

Physics
1 answer:
Pachacha [2.7K]4 years ago
6 0

Answer: 7.5(10)^{-7} m

Explanation:

The frequency \nu of an electromagnetic wave is given by the following equation:  

\nu=\frac{c}{\lambda}  

Where:  

c=3(10)^{8} m/s is the speed of light  in vacuum

\nu=4(10)^{14} Hz is the frequency of red light

\lambda   is the wavelength of red light

Isolating \lambda:

\lambda=\frac{c}{\nu}  

\lambda=\frac{3(10)^{8} m/s}{4(10)^{14} Hz}  

Finally:

\lambda=7.5(10)^{-7} m  

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Explain why nuclear fusion takes place only in the center of stars
iVinArrow [24]
 <span>A star is born when atoms of light elements are squeezed under enough pressure for their nuclei to undergo fusion. All stars are the result of a balance of forces: the force of gravity compresses atoms in interstellar gas until the fusion reactions begin. And once the fusion reactions begin, they exert an outward pressure. As long as the inward force of gravity and the outward force generated by the fusion reactions are equal, the star remains stable. Clouds of gas are common in our galaxy and in other galaxies like ours. These clouds are called nebulae. A typical nebula is many light-years across and contains enough mass to make several thousand stars the size of our sun. The majority of the gas in nebulae consists of molecules of hydrogen and helium--but most nebulae also contain atoms of other elements, as well as some surprisingly complex organic molecules. These heavier atoms are remnants of older stars, which have exploded in an event we call a supernova. The source of the organic molecules is still a mystery. 

STAR BIRTHS are started when the interstellar matter in gas clouds, such as the Eagle Nebula shown here, compresses and fuses. Irregularities in the density of the gas causes a net gravitational force that pulls the gas molecules closer together. Some astronomers think that a gravitational or magnetic disturbance causes the nebula to collapse. As the gases collect, they lose potential energy, which results in an increase in temperature. As the collapse continues, the temperature increases. The collapsing cloud separates into many smaller clouds, each of which may eventually become a star. The core of the cloud collapses faster than the outer parts, and the cloud begins to rotate faster and faster to conserve angular momentum. When the core reaches a temperature of about 2,000 degrees Kelvin, the molecules of hydrogen gas break apart into hydrogen atoms. Eventually the core reaches a temperature of 10,000 degrees Kelvin, and it begins to look like a star when fusion reactions begin. When it has collapsed to about 30 times the size of our sun, it becomes a protostar. When the pressure and temperature in the core become great enough to sustain nuclear fusion, the outward pressure acts against the gravitational force. At this stage the core is about the size of our sun. The remaining dust envelope surrounding the star heats up and glows brightly in the infrared part of the spectrum. At this point the visible light from the new star cannot penetrate the envelope. Eventually, radiation pressure from the star blows away the envelope and the new star begins its evolution. The properties and lifetime of the new star depend on the amount of gas that remains trapped. A star like our sun has a lifetime of about 10 billion years and is just middle-aged, with another five billion years or so left.</span>
4 0
3 years ago
Calculate the electric field associated to an electric dipole for two charges separated 10-8 m with a dipole moment of 10-33 C m
Alex Ar [27]

Answer:

18 N/C

Explanation:

Given that:

Electric field constant, k = 9*10^9 N/c

Distance, r = 10^-8 m

Dipole moment, p = 10^-33

Using the relation for electric field due to dipole :

E = [2KP / r³]

E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3

E = (18 * 10^9 * 10^-33) ÷ 10^-24

E = [18 * 10^(9-33)] ÷ 10^-24

E = (18 * 10^-24) / 10^-24

E = 18 * 10^-24+24

E = 18 * 10^0

E = 18 N/C

5 0
3 years ago
A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.180 m2. The coil is now stretched to hav
butalik [34]

Answer:

Explanation:

Given that,

Number of turns of coil

N = 50 turns

Initial area of plane

A1 = 0.18 m²

The coil it stretch to a no area in time t = 0.1s

No area implies that the final area is 0, A2 = 0 m²

Constant magnetic field strength

B = 1.51 T

EMF?

EMF is given as

Using far away Lenz law

ε = —N• dΦ/dt

Where Φ = BA

Then,

ε = —N• d(BA)/dt

Since B is constant,

ε = —N•B dA/dt

ε = —N•B (∆A/∆t)

ε = —N•B(A2—A1)/(t2-t1)

ε = —50 × 1.51 (0—0.18)/(0.1—0)

ε =—75.5 × —0.18 / 0.1

ε = 135.9 V

The induced EMF is 135.9V

Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.

Since the area lines in the plane, then the induced emf will be out of the page

5 0
4 years ago
You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abo
kvv77 [185]

Answer: plane speed is 94.87m/s

Explanation: since the plane move upward in a semicircular path, the acceleration is a centripetal acceleration with radius of 500metre. But the Centripetal acceleration is given as

Centripetal acceleration

= Speed ²/radius

Making speed subject of formula we have,

Speed² = centripetal acceleration*radius

Speed² = 18*500

=9000

Speed =√9000

= 94.87m/s

7 0
3 years ago
A block with mass M is placed on an inclined plane with slope angle q and is connected to a second hanging block with mass m by
tensa zangetsu [6.8K]

Answer:

The mass of the block m is:

m=M(sin(\theta)+\mu_{s}cos(\theta))

Explanation:

Let's analyze the block by parts

For the block M

T-W_{x}-f_{f}=0 (1)

Where:

  • T is the tension
  • W(x) is the component of the weight in the x-direction
  • F(f) is the friction force

T-Mgsin(\theta)-\mu_{s}N=0  

T-Mgsin(\theta)-\mu_{s}Mgcos(\theta)=0  

For the block m

T-W=0

T=mg (2)

Now, let's combines equation (1) and (2):

mg-Mgsin(\theta)-\mu_{s}Mgcos(\theta)=0  

Finally, let's solve it for block m.

mg-Mg(sin(\theta)+\mu_{s}cos(\theta))=0

m=M(sin(\theta)+\mu_{s}cos(\theta))

I hope it helps you!

7 0
3 years ago
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