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dalvyx [7]
3 years ago
5

If a scale drawing has a ratio of 1.5 inches to 20 feet,how many inches would be required for an actual distance of 75 feet?

Mathematics
1 answer:
ankoles [38]3 years ago
7 0
Let, that distance = x inches.
1.5/20 = x/75
x = 75×1.5 / 20
x = 112.5/20
x = 5.625

In short, Your Answer would be 5.625 in.

Hope this helps!
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Find the length of the segment with endpoints of (3,2) and (-3,-6).
MakcuM [25]
The formula of the length of the segment AB:
A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}
We have:
A(3;\ 2)\to x_A=3;\ y_A=2\\\\B(-3;\ -6)\to x_B=-3;\ y_B=-6
Substitute:
|AB|=\sqrt{(-3-3)^2+(-6-2)^2}=\sqrt{(-6)^2+(-8)^2}\\\\=\sqrt{36+64}=\sqrt{100}=10
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4 years ago
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tino4ka555 [31]
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IgorC [24]
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Center (-15,11) radius 2
kodGreya [7K]

Answer:

(x+15)^2+(y-11)^2=4

Step-by-step explanation:

<u><em>The question is</em></u>

How do you write an equation for a circle with center (-15,11) and radius 2?

we know that

The equation of a circle in center radius form is given by

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center of the circle

r is the radius of the circle

substitute the given vales

(x+15)^2+(y-11)^2=2^2

(x+15)^2+(y-11)^2=4

8 0
3 years ago
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