Answer:
B. .007
Step-by-step explanation:
Mean=μ=23500
Standard deviation=σ=7200
For sample of 50 students
Mean=μxbar=μx=23500
Standard deviation=σxbar=σ/√n=7200/√50=1018.23
So, the probability that mean outstanding loan for students is under $21000
P(xbar<21000)=P((xbar-μxbar)/σxbar<(21000-23500)/1018.23)=P(Z<-2.455)
P(xbar<21000)=P(Z<-2.455)
P(xbar<21000)=P(-∞<z<0)-P(0<z<-2.455)
P(xbar<21000)=0.5-0.4930=0.007
Thus, the probability that mean outstanding loan for students is under $21000 is 0.007.
1 Simplify
-∣−n∣>0 to
−n>0
2 Multiply both sides by −1
n<0
Answer:
N<0
So yes, this is possible.
I would certainly be willing to do that for you. But in order to write the composite function, I would first need to know the elemental functions ... f (x) and g(x).
The answer for 5 pack of batter is 7.10