Answer:
1st option
Step-by-step explanation:
The domain and range are all real numbers , that is
domain { x | x ∈ R }
range { y | y ∈ R }
10000 digits can be used for 4 digit A.T.M code.
<u>Solution:</u>
Given that A.T.M required 4 digit codes using the digits 0 to 9.
Need to determine how many four digit code can be used.
We are assuming that number starting with 0 are also valid ATM codes that means 0789 , 0089 , 0006 and 0000 are also valid A.T.M codes.
Now we have four places to be filled by 0 to 9 that is 10 numbers
Also need to keep in mind that repetition is allowed in this case means if 9 is selected at thousands place than also it is available for hundreds, ones or tens place .
First digit can be selected in 10 ways that is from 0 to 9.
After selecting first digit, second digit can be selected in 10 ways that is 0 to 9 and same holds true for third and fourth digit.
So number of ways in which four digit number is created = 10 x 10 x 10 x 10 = 10000 ways
Hence 10000 digits can be used for 4 digit A.T.M code.
Answer:
2 9/10
Step-by-step explanation:
subtract the 1 mile from the 3 9/10 mile. kinda like 3-1 but then you put the other stuff on the end (9/10)
I'm pretty sure this is the correct answer
Answer:
Step-by-step explanation:
Total number of tools for both = 564.
Dr Brown used 386 tools for 6 experiments.
average number of tools per experiment used by Dr Brown = 
= 64
Dr Rachal used 236 tools for 8 experiments.
average number of tools per experiment used by Dr Rachal = 
= 29
i. The number of more experiment that can be done by Dr Brown = (564 - 386) ÷ (64)
= 2.7668
Dr Brown can do two more experiments.
The number of more experiments that can be done by Dr Rachal = (564 - 236) ÷ (29)
= 11.1186
Dr Rachal can do 11 more experiments.
ii. Number of tools left after Dr Brown's experiments = 564 - 386
= 178
Number of tools left after Dr Rachal's experiments = 564 - 236
= 328
Answer: 290951.87
Step-by-step explanation:
Hope this helps :D
