Given, (9x - 4)(9x + 4) = ax² - b
From algebraic identities:
We know, (a + b)(a - b) = a² - b²
Now, 81x² + 36x - 36x - 16 = ax² - b
81x² - 16 = axis² - b
So ax² = 81x²
a = 81
-b = -16
b = 16
Solution
Therefore, the value of a is 81.
<h2>MyHeritage</h2>
Answer: They are not perpendicular because their slopes are not negative reciprocals.
Step-by-step explanation:
For these two lines to be perpendicular, their slopes have to be negative reciprocals.
Slope of FG.
F = (-4, 1)
G = (0, -2)
= (Y₂ - Y₁) / (X₂ - X₁)
= (-2 - 1) / (0 + 4)
= -3/4
Slope of HJ
J = (0 , 4)
H = (-4, -2)
Slope = (Y₂ - Y₁) / (X₂ - X₁)
= (-2 - 4) / (-4 -0)
= 6/4
= 3/2
<em>The slopes of these lines are not negative reciprocals so these lines are not perpendicular. </em>
A. you have to do the whole 30/2 i just had this on a test. GOOD LUCK
Answer:
AB=29; BC=27
Step-by-step explanation:
So they told us AB=4x+9 and that BC=5x+2, and AC=56 , now to help with the question you can draw this information on a number line. Now on a number you can see that basically AC=AB+BC.
So you would write it as such,,
4x+9+5x+2=56
Combine like terms
9x+11=56
Now you have to isolate the x by itself but first get rid of the 11.
9x+11-11=56-11
You would get
9x=45
Here you can divide 9 by both sides to isolate x.
9x/9=45/9
{x=5}
Now to find the value for both substitue x in the equations for both
1. AB=4x+9 where x is 5
4(5)+9 =AB
20+9 =AB
29=AB
You would do the same with BC
2. BC= 5x+2 where x is 5
5(5)+2= BC
25+2= BC
27=BC
If you want to check your answers you can just substitute x for 5 in the first equation we did where AC=AB+BC
