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VARVARA [1.3K]
3 years ago
10

Janie inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm. How much greater was the volume of air in the

larger ball than the smaller ball?
Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.

_______cm^3
Mathematics
1 answer:
jekas [21]3 years ago
5 0
Formula for volume of a sphere:  V = (4/3)pi*r^3

18 cm radius:  VR = (4/3)pi*(18 cm)^3
12 cm radius:  Vr = (4/3)pi*(12 cm)^3

Calculate both, and then subtract the 2nd from the first.  I would take the short cut of finding the difference as follows:

Difference in volume = (4/3)(3.14)*[18^3 - 12^3] cm^3
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What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

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