Answer:
for the first one it's 40 seconds
and for the second one I can't see the options but I I think it is 300
C is the hypotenuse, which is 10.
a^2 + b^2= c^2
(6)^2 + (8)^2= (10)^2
ANSWER: B) 6^2 + 8^2= 10^2
Hope this helps! :)
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Answer:
A: x + y = 55; y - x = 25
B: 15 minutes running
C: no
Step-by-step explanation:
<h3>Part A:</h3>
The two equations relate to the total number of minutes, and to the difference specified in the problem statement.
x + y = 55 . . . . . . total time is 55 minutes
y = x + 25 . . . . . . dances 25 minutes longer
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<h3>Part B:</h3>
We can substitute for y in the first equation to find the value of x, the time spent running.
x + (x +25) = 55
2x = 30 . . . . subtract 25
x = 15 . . . . . . divide by 2
Jackie spends 15 minutes running each day.
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<h3>Part C:</h3>
The value of y from is found using the second equation:
y = x +25 = 15 +25 = 40
Jackie <u>will not spend 45 minutes dancing</u> if she meets the requirements on times.
Use a let statement
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
-323 -323
x^2 + 2x -323 = 0
third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19
x = -17
hope this help
