Hi there!
The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Answer: i have a answer but it is not up there srry
Step-by-step explanation:
Answer:
We know that, two quantities are proportional when they vary directly with each other.
i.e. quantities x and y are proportional when they have the relation y = kx, where k is any constant called constant of proportionality.
Since, the quantities are in relation y = kx.
So, for x = 0 we get that the value of y = 0.
As, the point ( 0,0 ) satisfies this relation i.e. it is a solution of y = kx.
Hence, in proportional relationship, the graph will pass through ( 0,0 ).
