The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
Answer: 7/8
Step-by-step explanation:
1. w=2
2. x=2
3. y=-5
4. a=1
if these helped please mark brainliest
The relations are domain and range
